With downward buoyancy in a uniform rotating Boussinesq approximation, is time-independent. The linear pressure obeys . The initial potential vorticity supplies the steady pressure source; nonzero-frequency inertia-gravity waves have zero perturbation PV.
Non-Boussinesq pure-plume density transition 2026-10-14
For an ideal-gas heated pure plume with entrainment proportional to , the excess heat flux implies conserved kinematic buoyancy flux . Put , . Their balances are and , identical to the pi-suppressed Boussinesq pure-plume flux equations. With and , , and . The radius is and reduced gravity is . At density is half ambient; far above this height the Boussinesq approximation becomes accurate.
For two-dimensional flow under the Boussinesq approximation with , , a linear mode whose Laplacian is proportional to its streamfunction has zero self-advection of vorticity. Its buoyancy anomaly is , with . Self-advection of buoyancy vanishes only when the displayed Jacobian is zero. Constant stratification and constant flow make constant and yield finite-amplitude exact wave solutions. A varying polarization coefficient generally creates a second harmonic, even when the vorticity self-interaction vanishes.
Past exam of the mathematics course of the University of Cambridge 2001 iii Paper 43 1 a Solution Created 2026-10-03 Updated 2026-10-14
Take a dense lower layer and write . In the Boussinesq approximation the fractional density difference is small; use the reference density in inertia and retain the difference in buoyancy. The one-layer model additionally treats the ambient as much deeper, with negligible distributed horizontal inertia away from the head. The shallow water approximation requires depth small relative to the horizontal variation length, small vertical accelerations, nearly hydrostatic pressure, and an approximately depth-uniform horizontal velocity. Neglect mixing, viscosity, bed friction and rotation. A slowly varying rectangular channel allows cross-sectional averages without large lateral separation.
A slice of width contains volume . Its outgoing volume flux is , so volume conservation gives . The integrated hydrostatic excess pressure is . Pressure on the sloping side walls contributes to the longitudinal force. The conservative momentum equation is thereforeUse the volume equation to simplify it. The resulting shallow water equations areOmitting the wall force would incorrectly introduce a width term into the material acceleration equation.
For the principal matrix is . Its eigenvalues are , where . For they are real and distinct, so the system is strictly hyperbolic. It degenerates at a dry front. From the volume equation, . Combine this with the momentum equation to obtain the variable-width shallow-water characteristics:In a constant-width channel are Riemann invariants along the corresponding characteristic curves; with varying width they satisfy compatibility equations with a source term.
Past exam of the mathematics course of the University of Cambridge 2001 iii Paper 43 3 a Solution Created 2026-10-03 Updated 2026-10-14
For a rising light plume use in the Boussinesq approximation, with ambient density as the inertial reference. The full cross-sectional kinematic volume flux, momentum flux and buoyancy flux of a top-hat plume areHere momentum flux per unit reference density is meant, not momentum per unit volume. The Batchelor entrainment hypothesis says ambient fluid crosses the plume edge at mean inward speed , where is the dimensionless entrainment coefficient. Volume added per unit height is . With , the integrated plume balances in uniform ambient density areSeek a pure plume with no persistent source volume or momentum scale. Equating powers of gives and ; constant buoyancy gives . Equating coefficients yields, relative to the ideal source or a fitted plume virtual origin,Thus , and . A finite nozzle or nonzero source momentum requires a near-source transition rather than this singular point-source solution at arbitrarily small .
Past exam of the mathematics course of the University of Cambridge 2001 iii Paper 45 3 Solution Created 2026-10-03 Updated 2026-10-14
The cell conservation equation has the form , withThe first term is advection by the suspension's fluid velocity, the second is active swimming at fixed speed in direction , and the last is an isotropic diffusive flux due to random swimming. Here has units length squared per time, is cell number per volume, and the divergence measures local loss by transport. No birth or death term is included.
For a spherical cell of radius , its excess buoyancy force is . The Stokes drag law gives passive settling speed . Neglecting individual settling requires , not exact neutral buoyancy. A dilute suspension can still generate appreciable collective buoyancy because many small excess masses contribute to the bulk density.
Use the half-rate convention for the gyrotactic reorientation time , required by the coefficients printed in the question:The first torque tends to point the bottom-heavy cell upward; the second rotates a sphere with half the fluid vorticity. This is a quasistatic torque balance, assuming orientation relaxation is fast enough to follow the local flow. Keeping orientation dynamics instead would put on the left. The convention with aligning rate uses a reorientation parameter twice this . Thus the factor of two is a definition, not a physical discrepancy. Close to the upward state the quasistatic gyrotactic balance with half-rate reorientation gives .
For a dilute Newtonian suspension with the Boussinesq approximation, the other equations areThe background-water hydrostatic pressure is absorbed in . The cell volume is , density is , cell density is , dynamic viscosity is , and is the volume fraction. Extra cell mass produces the downward buoyancy term. Constant viscosity and no explicit swimming stress are part of this closure. Rigid impermeable plates impose no-slip boundary condition and zero normal total cell flux.
At rest, the stable cell direction is upward and the steady vertical flux is . It is constant in depth by conservation and zero at an impermeable plate, soThe pressure gradient balances its excess weight. The mean-concentration formula follows by averaging over and is continuous at .
Linearize with the horizontal Fourier mode and . Write the first-order orientation perturbation as . Unit length gives , while torque balance gives . Incompressibility impliesLet . The perturbation of fluid advection is , and swimming contributes . Cell conservation therefore givesorThis explains the destabilizing concentration-advection term and the gyrotactic redistribution term with their signs.
To eliminate pressure from the fluid equations, take their divergence, giving . Apply to the vertical equation . The concentration second derivatives cancel, leavingNo-slip conditions give and at each plate; for nonzero , the latter follows from the vanishing horizontal velocity and incompressibility. Zero perturbed normal cell flux givesThe normal orientation correction is zero at this order, and the fluid velocity is zero at the plate, so neither adds another term to this concentration condition.
Now use the stated distinguished scalings , , , , , and . Here is a scaled wavenumber, unrelated to Question 2's shear rate. At order one, the concentration equation and boundary conditions give , at both endpoints, so is constant. Absorb its nonzero value into the perturbation amplitude and chooseAt order , the fluid equation is with at both ends. Its unique solution isA homogeneous difference is cubic and the four clamped conditions make it zero.
The concentration equation at order givesso , where fixes the amplitude normalization. At order it givesThe boundary conditions expand to at each endpoint. Integrating this equation from zero to one cancels against . Also andThus the required solvability condition isSince , the clamped-quartic solvability in shallow bioconvection gives
For nonzero long horizontal waves, gives decay and gives growth; the leading neutral threshold is . The leading instability is stationary and independent of and . The exactly uniform horizontal mode has zero growth at this order because total cell number is conserved, so it does not determine the threshold. Upward swimming produces a dense upper layer; the unstable disturbance is its buoyancy-driven overturning, or bioconvection. Higher orders are needed for wavelength selection and finite-depth threshold corrections.
With fixed material parameters and mean concentration, for small , so a sufficiently thin chamber is stable to this branch. Formally its threshold corresponds to when the weak-stratification and distinguished-gyrotaxis assumptions apply. In particular, the assumed is a specified asymptotic analysis; at fixed and decreasing , one instead has . The leading result should not be asserted unchanged in that different ordering without redoing the expansion.
Past exam of the mathematics course of the University of Cambridge 2001 iii Paper 48 3 Solution Created 2026-10-03 Updated 2026-10-14
The quasi-geostrophic approximation isolates slowly evolving, nearly balanced motions in a rotating, stably stratified fluid. Ocean eddies and mid-latitude atmospheric disturbances often have this character: a leading Coriolis force–pressure balance suppresses rapid horizontal acceleration, while hydrostatic balance suppresses rapid vertical acceleration. Small ageostrophic flow nevertheless supplies the vertical motion that changes the leading vorticity. The approximation filters fast inertia-gravity waves while retaining nonlinear transport, vertical shear and Rossby waves.
Use a reference density and remove the background hydrostatic pressure. Let and let the upward buoyancy perturbation be . A vertically varying reference density stratification has . Under the Boussinesq approximation, the inviscid and adiabatic equations areHere . Density variations are small compared with but retained in the vertical buoyancy force. This is a useful local, incompressible description; a compressible atmosphere needs the corresponding weighted or pressure-coordinate version.
Let horizontal and vertical lengths be , speed be , and take the slow time . Take for definiteness; use in the scale estimates in the opposite hemisphere. The principal small parameter is the Rossby number at a latitude where . For the hydrostatic, strongly stratified regime, and . Retaining both horizontal vorticity and vortex stretching gives the Burger numberThe geostrophic balance pressure scale is and the buoyancy perturbation scale is . Hence : buoyancy perturbations produce small displacements relative to the background stratification scale. The ageostrophic flow is and incompressibility then gives . Vertical acceleration is smaller than hydrostatic terms by order in this scaling. Weak forcing or diffusion can be added at the slow order, but neither is present here.
Define the quasi-geostrophic streamfunction by . Leading geostrophic balance and hydrostatic balance implyDifferentiating horizontally and vertically gives the thermal-wind balanceThus vertical shear is determined by horizontal buoyancy gradients. The homogeneous Taylor–Proudman theorem is recovered only when those gradients vanish. Stable stratification allows sloping density surfaces and different geostrophic flow at different levels, without abandoning leading balance.
The Prandtl ratio of scales makes that modification quantitative. Horizontal and vertical terms in balanced potential-vorticity inversion have sizes and . Equality givesFor constant , makes the inversion operator an ordinary three-dimensional Laplacian. Equivalently, an interior balanced disturbance of horizontal size naturally penetrates a depth of order . With this is a thin, vertically sheared structure, rather than the arbitrarily tall homogeneous columns suggested by strict Taylor–Proudman theorem behaviour. This is an aspect-ratio statement, not the diffusivity Prandtl number.
To allow a weak meridional variation of the Coriolis parameter, use the beta plane , with , or equivalently . The small correction to the leading balance is dynamically important on the slow time. Let be vertical relative vorticity and let . At the first nontrivial order, the vertical vorticity equation and buoyancy equation reduce toRelative-vorticity stretching and tilting are higher order here; planetary-vorticity stretching must remain. Eliminate to expose a materially conserved balanced scalar. Because , the commutator term is exactly zero. For this givesAdding the two equations proves the quasi-geostrophic potential-vorticity equationAn additive constant such as changes no dynamics. The horizontal streamfunction advection bracket can express this as . Although small departures from balance generated this evolution equation, the leading geostrophic flow itself advects nonlinearly. The stretching term couples horizontal motion to vertical displacement of density surfaces.
This gives the practical advection-and-inversion description. Start with interior three-dimensional quasi-geostrophic potential vorticity, advect it with , and recover fromThe stratified quasi-geostrophic inversion is elliptic for positive . It must be supplied with lateral and vertical boundary conditions and any circulation or mean-flow constraints; interior potential vorticity alone is not sufficient. At rigid horizontal lids, makes boundary buoyancy satisfy , and supplies the vertical derivative data for inversion. Boundary buoyancy perturbations can therefore support flow even when the interior anomaly is zero. Once is found, its horizontal derivatives give velocity, its vertical derivative gives buoyancy, and the thermodynamic equation diagnoses . This balanced evolution excludes the independent fast-wave initial data present in the full equations.
Finally, a gradient in supplies a restoring mechanism even in an otherwise uniform fluid. Linearizing about rest with constant , the quasi-geostrophic potential-vorticity equation becomesSubstitution of gives the Rossby wave dispersionFor , its zonal phase speed is westward relative to a resting background. A meridionally displaced parcel retains potential vorticity, so it acquires a relative-vorticity anomaly that induces the velocity tending to return the disturbance. Background shear and stratification modify the full potential-vorticity gradient; they can alter propagation or permit instability. On a constant f-plane the planetary contribution vanishes, but gradients of relative vorticity, boundary buoyancy or topography can still support balanced wave motion. Close enough to the equator that vanishes, this mid-latitude quasi-geostrophic approximation and its scaling must be replaced.
Past exam of the mathematics course of the University of Cambridge 2002 iii Paper 43 4 Solution Created 2026-10-03 Updated 2026-10-14
Magnetic flux concentration and flux expulsion describe redistribution of an existing field, not necessarily creation of net flux. For a weak field in a prescribed conducting flow, the resistive induction equation isIts ideal part combines transport, stretching and compression:Thus a converging flow can intensify a component, and stretching can increase magnetic energy even if the signed net flux is zero. At large magnetic Reynolds number , diffusion is initially slow on the eddy scale, so magnetic flux freezing carries field lines with the flow. These statements do not imply that an ideal closed eddy can simply lose its initially enclosed flux.
The missing step is the production of small scales by differential circulation. In a two-dimensional incompressible eddy, the Cartesian magnetic flux function obeysDifferent streamlines have different circulation rates. An initially smooth field is wound into fine folds; diffusion and reconnection then smooth the variation of inside the eddy. As becomes nearly uniform there, its gradient and hence the interior magnetic field become small. The surviving flux lies mainly near the circulation boundary and adjacent separatrices, where stronger gradients remain. This is flux expulsion. With exactly zero diffusivity, field topology and the flux of material loops remain frozen, so a relaxed flux-free interior is not obtained by pure advection alone. Rigid rotation also fails to generate the differential winding responsible for this process.
The phase mixing in magnetic flux expulsion estimate makes the enhanced role of small diffusion explicit. If the angular-velocity gradient is of order , a wound radial wavenumber grows as . The accumulated damping exponent is of orderIt becomes order one atThis is much shorter than the large-scale diffusion time at large , but longer than one turnover time. It is a kinematic differential-shear estimate, not a universal time for every turbulent or rapidly evolving convection cell.
A related concentration mechanism occurs at converging flow boundaries. For a locally vertical bundle, conservation of flux gives , so reducing its cross-section increases . In a simple converging boundary region with strain rate , balancing strain and transverse diffusion givesThis is the thickness estimate for that local strain-diffusion model; it need not be the thickness or energy scaling of every closed-eddy flux-expulsion problem. Stronger field eventually exerts Lorentz force feedback and changes the flow. The equipartition magnetic field is a useful indication that the kinematic assumption can fail, not a universal upper bound on concentrated fields.
At the Sun's photosphere, hot upflows form solar granules, and their spreading horizontal motion transports weak vertical field toward cooler intergranular lanes and downflows. A thin-layer illustration, neglecting vertical transport terms, is . It gives : horizontal convergence intensifies the vertical flux density. This surface transport is related to the redistribution by convective eddies, but is not identical to the closed-streamline mechanism in the preceding planar example. Larger-scale supergranulation also gathers magnetic elements toward its boundaries, helping organize the solar magnetic network.
Concentration can be further intensified by compressible thermal dynamics. In the thin-tube picture of convective collapse, an unstable downward flow drains gas, reduces internal pressure and allows contraction at approximately conserved flux. Lateral balance then permits field stronger than the local kinetic equipartition estimate. This evacuation mechanism is excluded by a strict Boussinesq approximation. It is not a description of every evolving surface concentration: gas pressure, dynamic stresses and magnetic curvature can all matter when thin-tube equilibrium fails. The resulting strong, intermittent magnetic elements are associated with intergranular structure; their radiative appearance also depends on thermal structure and opacity. The organized fields of sunspots require a broader account of flux supply and magnetic feedback, rather than attribution to weak-field expulsion alone.
Thus convection redistributes and concentrates flux, finite diffusion enables classical expulsion, and nonlinear magnetic and thermal feedback determines the strong-field outcome. An expulsion argument alone neither supplies the original solar field nor establishes a self-sustaining solar dynamo.
Past exam of the mathematics course of the University of Cambridge 2002 iii Paper 52 3 b Solution 2026-10-14
Write . The Saint-Venant dry-front condition describes a liquid advancing over a dry bed, or into an ambient whose inertia is negligible, as when . The edge has ; its velocity is obtained by continuing the appropriate shallow water Riemann invariant to zero depth. There is no independent universal finite-depth head Froude number. In the triangular geometry a release of a resting layer gives , whereas a rectangular release gives .
The Benjamin deep-ambient front condition includes the inertia of an ambient that must turn around a finite-depth gravity current head. In the ideal deep-ambient Boussinesq approximation, is close to one andHere is the current depth just behind its head, its speed relative to the far ambient, and the ideal head Froude number. The ambient is much deeper than ; a finite upper-layer depth changes the closure. The lower density must exceed the ambient density for a bottom current. A non-Boussinesq head requires an appropriate density-ratio correction rather than using at every ratio. The Saint-Venant and Benjamin models therefore describe different front physics, even though both use the same long-wave equations in the interior.
Past exam of the mathematics course of the University of Cambridge 2002 iii Paper 52 5 b Solution 2026-10-14
In the top-hat plume model, vertical velocity and reduced gravity are uniform over . The ambient has zero vertical velocity, negligible ambient turbulence and a prescribed . Thenand the equations becomeEquivalently, the ordinary differential equations for the three unknowns areThe last equation displays dilution by fluid entrainment as well as loss of relative buoyancy while rising through a stably stratified ambient. The model assumes a steady slender two-dimensional turbulent plume, large Reynolds number, the Boussinesq approximation, constant and , negligible heat loss, negligible imposed crossflow, and negligible pressure departure from ambient hydrostatic pressure. The factors of two count both entraining edges; is a half-width. A finite source also requires its volume, momentum and buoyancy fluxes as boundary data.
Past exam of the mathematics course of the University of Cambridge 2002 iii Paper 52 6 a Solution 2026-10-14
Use the Boussinesq approximation and a top-hat plume model. Let be the uniform ambient return velocity outside the plume. Negligible source volume flux and an impermeable cylindrical wall require zero net transport through every horizontal section:The entrainment speed must be specified relative to that moving ambient. Taking it to be givesThe surrounding unmodified fluid has zero buoyancy relative to the initial fluid. Neglecting thermal or compositional loss therefore givesLet denote the conserved specific source buoyancy flux: if is the actual integrated source flux, or if the source strength has already been normalized by .
To obtain the usual integral-model singularity one must also state a pressure closure. Here take the whole-section mean pressure to have only its reference ambient hydrostatic pressure, and neglect wall force and extra vertical turbulent-stress fluxes in the integral budget. Internal momentum transfers between plume and ambient cancel in that whole-section balance. The remaining upward force is the plume buoyancy, givingThe two momentum fluxes add, even though is negative: vertical momentum transported downward also contributes to the flux through an upward-oriented horizontal section. These three flux balances, with the algebraic return-velocity constraint, govern in the confined plume with compensating return flow.
The pressure-neglecting closure is an integral approximation, not a claim that the return fluid has zero acceleration. If a mean pressure departure is retained, the whole-section momentum balance instead contains , along with any wall-force or stress contribution. The entrainment hypothesis alone does not specify that function. The singularity calculated below belongs to the stated pressure-neglecting model; it is not forced by continuity alone or asserted to be an infinite velocity in the real fluid.
Past exam of the mathematics course of the University of Cambridge 2003 iii Paper 76 3 a Solution 2026-10-14
The shallow-water approximation requires the depth to be small compared with the horizontal scale of variation, small vertical accelerations and nearly hydrostatic pressure. Take cross-sectionally uniform lower-layer velocity and a sufficiently deep, effectively stationary upper layer. Under the Boussinesq approximation, is the reduced gravity. Conservation of lower-layer volume gives constant discharge .
Dividing the Bernoulli equation by gives the shallow-water specific energyAt fixed , the energy curve has its minimum at the critical depth , where . Above this minimum there are two depth branches: deeper subcritical flow has , and shallower supercritical flow has .
The two long-wave speeds relative to the bed are . In subcritical flow one family can propagate upstream and one downstream; in supercritical flow both travel downstream for . At hydraulic control, , and a smooth transcritical solution must also satisfy the geometric regularity condition. The flow may remain entirely on either branch, cross smoothly through the control from subcritical to supercritical, or take the reverse smooth branch under appropriate boundary conditions. A downstream hydraulic jump can return supercritical flow to the subcritical branch while losing energy.
Depth branches in a contracting and expanding channel, including hydraulic control and a dissipative hydraulic jump
. Details. Past exam of the mathematics course of the University of Cambridge 2003 iii Paper 76 5 a Solution 2026-10-14
Use the flux normalization of the supplied equations, with the common factor suppressed. Put , and . The top-hat plume model reduces toEliminate height to obtain . Integrating with zero source volume and momentum flux gives the pure plume balanceEquivalently, seek and . The volume balance gives , and the momentum and buoyancy balances give and . ThusA finite source replaces the singular point origin by a plume virtual origin and source conditions. The Boussinesq approximation requires the fractional density difference to be small, so density can be replaced by ambient density in inertia and entrainment while retaining the small difference in buoyancy. In this solution it requires . The approximation necessarily fails sufficiently near the ideal point source, where diverges, and can also fail for strongly heated or otherwise large-density-contrast sources. The similarity solution is appropriate farther away once entrainment has diluted the anomaly, assuming a uniform ambient, constant entrainment coefficient and negligible confinement, heat loss and stratification.
Past exam of the mathematics course of the University of Cambridge 2003 iii Paper 76 6 a Solution 2026-10-14
Assume Boussinesq approximation, no wind, a uniform exterior, negligible source volume, sharp well-mixed internal layers, point-source pure plume entrainment and thin openings represented by discharge coefficients . Let be the upper-layer reduced gravity. Steady volume conservation makes the magnitudes of inlet and outlet flow equal to .
If the opening pressure drops are and , the orifice laws and hydrostatic pressure difference giveDefine the reduced area byThen the throughflow in this displacement ventilation model isLower-layer conservation requires . Global buoyancy conservation gives . Eliminating yieldsThis uniquely determines an interface height between zero and for a given positive area parameter. Opening area controls the nondimensional height; source strength controls the density contrast and flow magnitude. Factors of two depend on the stated effective-area convention, which has been fixed explicitly here.
Past exam of the mathematics course of the University of Cambridge 2004 iii Paper 73 2 Solution Created 2026-10-03 Updated 2026-10-14
Let , , and define the quasi-geostrophic streamfunction by . Use horizontal scale , vertical scale , velocity scale and advective time . The required quasi-geostrophic approximation has small Rossby number , , and Burger number . Hydrostatic, thin-layer scaling has ; density variations are small compared with , as required by the Boussinesq approximation. The leading horizontal flow is nondivergent, with vertical velocity . Retain forcing of the same slow order as density advection, ; stronger forcing need not preserve this balanced scaling.
Leading geostrophic balance and the hydrostatic approximation giveWrite . The density equation becomesTaking the curl of the horizontal momentum equations at the next order and using continuity gives the stretching equationSubstitute the expression for . Vertical differentiation commutes with the geostrophic material derivative acting on here: the extra Jacobian is . Since depends only on height, this yields the diabatically forced quasi-geostrophic potential vorticity equationThe minus sign is appropriate to the specified density forcing; a positive upward buoyancy forcing is and gives .
Now take constant and linearize about rest. Put and . The forced equation isFor the harmonic heating response of quasi-geostrophic flow, represent the two traveling Fourier components with frequencies and :Each component of the forcing has amplitude , soEquivalently its vertical structure obeysThese are the time-periodic forced responses; unspecified initial data may add free Rossby waves. Selecting no incoming waves describes forcing switched on causally and then its persistent harmonic part.
For , the eastward component always has . Let . The growing exponential would introduce an unbounded velocity and pressure disturbance at infinity, so discard it. The bottom condition then givesIf , this expression has the regular limit , rather than a physical singularity.
For , the westward component also has positive . Choose and use the same decaying expression with minus subscripts, including the same coincident-exponent limit. Thus both components are vertically evanescent above the heating.
For , putBoth homogeneous solutions are bounded, so boundedness is insufficient. A free Rossby wave with phase hasThe radiation condition demands energy propagation away from the heating, upward into . For that selects positive , hence in the westward component. The resulting solution isIt satisfies and, away from the decaying forcing, . Its far-field amplitude does not decay in this nondissipative model: continuous forcing supplies an outgoing wave train. Thus the low-frequency westward component propagates vertically while the eastward component remains evanescent.
At the threshold , the westward vertical wavenumber is zero. Excluding the linearly growing homogeneous solution and retaining the bottom condition gives . This bounded limiting response tends to a constant and has zero vertical group velocity; demanding both bottom zero and decay to zero at infinity would overdetermine this threshold problem. For , the branch labels and propagation inequality must be reconsidered; the comparison stated here assumes the usual positive beta-plane gradient.
Past exam of the mathematics course of the University of Cambridge 2004 iii Paper 75 2 a Solution Created 2026-10-03 Updated 2026-10-14
Write for the thermal expansion coefficient, for kinematic viscosity, for thermal diffusivity, and for thermal conductivity. For a temperature difference across depth ,The four-thirds convective heat-transfer law posits at high Rayleigh number, and thereforeThe layer depth cancels. A useful physical justification is a mixed interior with thin conductive boundary layers of thickness , each maintained near a fixed critical local Rayleigh number: and . Eliminating gives the exponent . Whether denotes the whole-layer contrast or the drop across one boundary layer changes the coefficient, not the exponent.
Assume Boussinesq approximation, constant material properties, a laterally extensive statistically turbulent Rayleigh-Bénard convection layer, negligible side-wall heat transfer, no rotation or imposed shear, approximately uniform bulk temperature, and the same specified Prandtl number regime when choosing . The closure is empirical and regime dependent; high Rayleigh number alone does not make it exact or extend it to the impulsive conductive initial transient.
Past exam of the mathematics course of the University of Cambridge 2004 iii Paper 75 3 b Solution Created 2026-10-03 Updated 2026-10-14
Put and , the reduced gravity. Use the Boussinesq approximation, hydrostatic pressure, uniform vertical velocity and concentration profiles, negligible fluid entrainment and drag, and a flat bed. Integrating volume conservation, momentum conservation and the particle budget over the layer givesThe hydrostatic pressure resultant is ; the last right-hand side is the deposition flux. With , these areThe quasilinear coefficient matrix in variables isIts eigenvalues are , where . Therefore the characteristic curves and their compatibility ordinary differential equations areFor the last equation the left eigenvectors are , and multiplying the quasilinear equations by them gives the displayed source terms. This is the sedimenting rectangular-channel characteristic compatibility relation; it supplies one differential relation on each wave family, rather than three independently closed scalar equations there. The contact eigenvector has and . For reference, an equivalent form isOnly for constant without settling do become genuine Riemann invariants. With settling, the spatial buoyancy gradient cannot be silently omitted.
Past exam of the mathematics course of the University of Cambridge 2004 iii Paper 75 4 a Solution Created 2026-10-03 Updated 2026-10-14
Let and . The four balances describe, respectively, fluid entrainment through the spherical surface at normal speed , the increase of vertical momentum due to buoyancy, conservation of total buoyancy in a uniform ambient, and motion of the thermal centre. Entrained ambient fluid initially has no vertical momentum, so the momentum equation includes the inertia needed to accelerate it. This model neglects added mass and drag; these effects would alter the numerical similarity coefficients.
With , the Boussinesq approximation replaces inertial density by while retaining the density difference in buoyancy. Take to this accuracy. ThenFor a point source, and the initial integrated impulse is zero. Therefore and . Integrating yieldsThe mass density follows from conserved buoyancy:Thus the radius and rise height grow as , the rise speed decays as , and the density deficit decays as . In height coordinates, put and ; then and .
If a reference density different from the inertial ambient density is retained, : replace in the kinematic formulas by , while retaining the original in the density-deficit formula. This keeps reference-density normalization separate from the physical acceleration.
The point-source spherical thermal similarity is singular at and cannot satisfy the small-density-difference condition arbitrarily close to its formal origin. A finite-radius, zero-impulse regularization has and , with . This displays the required initial data rather than attributing the singularity to a physical infinite initial speed.
Past exam of the mathematics course of the University of Cambridge 2004 iii Paper 75 6 a Solution Created 2026-10-03 Updated 2026-10-14
The Batchelor entrainment hypothesis assumes that the mean ambient inflow normal to the edge of a turbulent turbulent plume is proportional to its representative axial velocity, . With top-hat plume model fields and circumference , the added volume per height is . It is an integral turbulent mixing closure; it does not assert that every instantaneous eddy has the same inward speed. Use constant positive , uniform resting ambient, Boussinesq approximation, negligible drag and no buoyancy loss.
Since , . Eliminate between the volume and momentum balances:The zero-source-flux condition gives , the pure plume balance. Substitution in and integration givesRecovering the top-hat fields from , and yieldsThe paper's ratio is thereforeThis is the constant inverse-normalized ratio used here, not the catalog's normalized plume balance parameter, which is one for a pure plume. The zero-flux point source is a limiting similarity origin: the speed and density anomaly diverge there, so a physically finite source must regularize the near field. The expressions are valid in the region where the Boussinesq approximation and turbulent closure apply.
