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A redox chemical reaction couples oxidation and reduction. In the electrode examples here, oxidation releases electrons and reduction accepts them. ^[ref]

Redox can be recognized by changes in oxidation state: an increase records oxidation, a decrease reduction. These are formal electron assignments, distinct from measured partial atomic charges. Half-reactions expose the matching loss and gain, making electric charge conservation visible.^[ref]

The electron accounting need not describe free electrons travelling between spatially separated chemical species. For example, in $2{\mathrm{H}}_2+{\mathrm{O}}_2⟶2{\mathrm{H}}_2\mathrm{O}$, hydrogen changes from oxidation state $0$ to $+1$ and oxygen from $0$ to $-2$. Four hydrogen chemical atoms lose four formally assigned electrons in total; two oxygen chemical atoms gain four. The water product has covalent bonds, and these assignments do not turn it into separated ions. See ionic approximation of bonds and electron transfer and ionic character.

By contrast, neutralization can rearrange chemical bonds without changing oxidation states:Hydrogen remains $+1$ and oxygen remains $-2$. The aqueous proton notation abbreviates its interaction with water. This acid-base chemistry example conserves electric charge but has no matching increase and decrease of oxidation state; movement of ions or a change of chemical bonds alone does not establish redox.

Consider the reacting zinc and copper species in the zinc-copper displacement experiment. Split the net chemical equation into two half-reactions:

The zinc oxidation state rises from $0$ to $+2$; the copper oxidation state falls from $+2$ to $0$. Add the half-reactions: two released electrons match two accepted electrons. Cancelling $2e^{-}$ from both sides gives^[ref]Thus the closed net chemical reaction has zero net production of free electrons. Cancellation does not destroy electrons: it removes a matched internal exchange from the written chemical equation. The half-reactions alone are incomplete descriptions of the whole reacting system. In a galvanic cell, the exchange can pass through a wire; in the zinc-copper displacement experiment, the reacting materials meet at the same metal surface. The equations do not require a reservoir of free electrons in the bulk chemical solution.

Check both kinds of balance. The oxidation line has net electric charge $0$ on the left and $(+2-2)e=0$ on the right; the reduction line has $(+2-2)e=0$ on the left and $0$ on the right. The net chemical equation contains one zinc and one copper chemical atom on each side and has net electric charge $+2e$ on each side, where $e$ is the positive elementary charge. The written reacting species need not be electrically neutral as a group: the bulk chemical solution also contains compensating anions.

There is an even more literal check. Zinc has atomic number $30$ and copper $29$, so the initial pair contains $30+(29-2)=57$ electrons. The final pair contains $(30-2)+29=57$ electrons. Only their distribution has changed. Conserved chemical element counts give the usual chemical mass conservation inventory; changing the counts of neutral and charged species does not create or remove their atomic nuclei.

Matching electrons is necessary but does not replace balancing every chemical element. The acidic permanganate-iron balance illustrates unequal one- and five-electron exchanges, with water and protons also needed. Conversely, a balanced chemical equation alone establishes neither a reaction rate nor a detailed mechanism. Its usefulness is that it fixes the stoichiometry even when those additional questions remain open.

A reducing agent undergoes oxidation by supplying the formal electron inventory. In the zinc-copper displacement experiment, metallic zinc plays this role.^[ref]

Glycolysis converts glucose into two pyruvate molecules, with a net two ATP and reduced NADH; it does not directly consume molecular oxygen. Pyruvate processing and the citric acid cycle, also called the TCA cycle, release carbon dioxide and supply reduced carriers. Thus releasing carbon dioxide and consuming molecular oxygen occur at different stages.^[ref]

An electron transport chain reoxidizes carriers such as NADH. Coupling some of its redox steps to proton transport establishes an electrochemical gradient; ATP synthase can use that gradient to form ATP from adenosine diphosphate and inorganic phosphate. This is oxidative phosphorylation. A separate route, substrate-level phosphorylation, transfers a phosphate group from a reacting substrate to adenosine diphosphate. In typical eukaryotic biological cells, the respiratory chain occupies the inner membrane of a mitochondrion.^[ref]

The useful achievement is controlled transfer: fuel oxidation can replenish an ATP supply that supports active transport and synthesis. ATP is a reusable chemical carrier, not newly created energy; ATP hydrolysis and the coupled cellular process have their own net free energy balance. Some fuel energy is dissipated as heat.^[ref]

There is no universal yield of $36$ or $38$ ATP per glucose. Actual ATP recovery depends on carrier transfer routes, coupling and diversion of intermediates to other metabolism. In particular, an oxygen uptake rate cannot be converted into an ATP production rate by assuming one fixed multiplier.^[ref]

The respiratory quotient compares carbon dioxide production with molecular oxygen consumption over the same interval. Complete glucose oxidation in the net equation above gives $\mathrm{RQ}=6/6=1$. In the ideal respirometer gas balance with no absorber, $f=0$, that conversion gives $D=0$: substantial cellular respiration can occur without any net gas contraction. A zero contraction therefore does not by itself demonstrate zero metabolism.

Other fuels, incomplete conversion and concurrent synthesis can alter the ratio. Absorber-based respirometry isolates molecular oxygen uptake by deliberately removing the other gas signal; it cannot independently determine the respiratory quotient or identify glucose as the consumed fuel. Separate carbon dioxide measurement would supply the missing account.

Respiratory uncoupling allows proton return to bypass ATP synthase, dissipating the electrochemical gradient. Electron transport and oxygen consumption can continue while less ATP is recovered.^[ref]

In the thermodynamic example under chemiosmosis, reducing both the activity ratio to one and the electric potential difference to zero removes the driving contribution. The hypothetical ATP-forming conversion then costs $+45\mathrm{kJ}\mathrm{mo}{\mathrm{l}}^{-1}$. Continued donor oxidation would not restore coupling unless it rebuilt a usable electrochemical gradient. This distinction makes respiratory uncoupling useful conceptually: abundant oxygen consumption can coexist with poor recovery of ATP.

The motivating question was experimental: how could one recover the order in a protein when breaking all its peptide bonds destroys that order? Frederick Sanger and colleagues used complementary tests on portions of insulin. The following is an explanation of their evidence, not a laboratory recipe.

First, mark ends before destroying the chains. Sanger used the colored reagent fluorodinitrobenzene, abbreviated FDNB, to label free amino groups. After acid hydrolysis, the attached label remained on the end-residue products. Separating these derivatives by their different movement through solvents and comparing them with reference derivatives made the labels readable. The N-terminus products identified glycine and phenylalanine. Sanger emphasized that finding a stable label and a way to separate its products were both essential. See Sanger, Citation Classic (1985), discussing The free amino groups of insulin (1945). FDNB also labels suitable free amino groups on amino acid side chains, so a labeled product is not automatically an N-terminus product. See Sanger, The Chemistry of Insulin, Nobel lecture (1958), pp. 546–547.

Next, separate chains and preserve local order. Oxidation with performic acid broke the protein disulfide bonds, allowing A and B chains to be isolated. Partial hydrolysis and enzyme treatments produced fragments; these were separated and their composition and local sequences characterized. Overlaps between different fragment sets linked smaller sequences into longer ones. Many more fragments than minimally necessary were checked for consistency. See Sanger's authored Nobel lecture, pp. 547–552: chain separation, fragment analysis and sequence reconstruction.

The toy fragments make the logic visible. Suppose one cut pattern yields MAG and AMG, and another yields MA, GA and MG. The first set alone permits MAGAMG or AMGMAG. The fragment GA in the second set crosses the MAG–AMG boundary in MAGAMG; it does not occur in AMGMAG. Among concatenations of the first set, therefore, the second set selects MAGAMG. This example assumes intact, correctly identified fragments from one homogeneous chain and known fragment membership in each cut pattern. Repeated stretches, missing fragments or sample mixtures can leave ambiguities; the picture illustrates inference from overlaps, not a universal guarantee of reconstruction.

Finally, determine the protein disulfide bonds separately. Oxidation used to separate whole chains erases their original connections. Sanger and colleagues instead studied fragments still joined by protein disulfide bonds, then oxidized the isolated joined fragments to identify their component pieces and locate the connected chain regions. An important trap was rearrangement of disulfide bonds during treatment: products can acquire connections absent from the starting protein. Their work therefore had to establish conditions that prevented rearrangement before interpreting a linked fragment as evidence. See Ryle and Sanger, A Disulphide Interchange Reaction, Nature 171, 1025–1026 (1953) and Sanger's Nobel lecture, pp. 553–554: preserving and identifying disulfide connections. The result was an experimentally constrained chemical structure rather than a composition list or a photograph of a fold.

A syn elimination in which oxidation of an organoselenide permits intramolecular beta-hydrogen removal and C–Se cleavage, producing an alkene.

The molecule $\mathrm{S}{\mathrm{O}}_2$ is emitted by volcanism and combustion and can be oxidized into sulfuric acid/sulfate. Direct gas deposition competes with gas-phase and aqueous oxidation. The precursor-gas lifetime and the resulting particle lifetime are different quantities.

A thiol is a chemical compound of the form $\mathrm{R}-\mathrm{SH}$, with an organic group $R$ attached to sulfur. The conjugate base is $\mathrm{R}-{\mathrm{S}}^{-}$; cysteine and mercaptoethanol supply examples of thiol groups. Two thiol groups can undergo oxidation to form a disulfide bond. ^[ref]