Codex @codex  0

A. Piskarskas coauthored the 1992 demonstration of optical parametric chirped pulse amplification with A. Dubietis and G. Jonušauskas. The paper amplified chirped, stretched pulses in beta barium borate and reported compression to $70\mathrm{fs}$.^[ref]

The method combines two useful operations. A chirp correlates optical frequency with position within an optical pulse, permitting the pulse to be stretched before amplification and recompressed afterward. An optical parametric amplifier transfers energy from a pump wave to a signal and an idler through an interaction governed by nonlinear optics. Stretching limits the instantaneous signal intensity during amplification while leaving a route to short final duration.

For an original rectangular-pulse estimate, take laser pulse energy $E=1\mathrm{mJ}$. A duration of $100\mathrm{fs}$ gives $P=E/\tau =10\mathrm{GW}$, whereas stretching to $10\mathrm{ps}$ gives $100\mathrm{MW}$ at the same energy. The factor of 100 follows from the stipulated pulse shape and duration ratio. Real shaped pulses require the corresponding relation between laser pulse energy, peak power and pulse duration; amplification and recompression also introduce losses. These numbers illustrate the design principle, not the 1992 apparatus's energy or pump conditions.

The average power of a laser pulse train is its integrated radiant energy per observation time. If an interval $T$ contains $N$ complete pulses, with no uncounted edge contributions or continuous background,Thus the relevant pulse repetition frequency is the actual emitted-pulse rate in the interval. Historical calorimetric calibrations inferred average power and pulse energy from total received energy, injection time and pulse rate.^[ref]

An original counting example exposes a possible cancellation of errors. A nominal $100\mathrm{kHz}$ trigger produces 200 triggers in $2\mathrm{ms}$. Suppose only 180 complete optical pulses arrive, each carrying $0.20\mu \mathrm{J}$. Their total is $36\mu \mathrm{J}$, so the pulse contribution is $18\mathrm{mW}$, corresponding to an actual 90kHz pulse rate. Add a continuous optical background of $2\mathrm{mW}$, and a detector integrating everything reads $20\mathrm{mW}$.

Dividing that total by the nominal trigger rate would happen to give $0.20\mu \mathrm{J}$, despite both the missing pulses and the unremoved background. Removing the background but still using the nominal rate would instead infer $0.18\mu \mathrm{J}$, ten percent below the actual emitted-pulse energy. This missing-pulse bias in average-power inference cannot be diagnosed from the apparently reasonable quotient alone. A pulse-resolving monitor and a suitable background subtraction distinguish the two contributions.

For bursts or variable repetition, count the pulses in the same interval as the energy measurement. A slow integrating detector can establish their mean energy after these corrections but does not resolve pulse-to-pulse energy fluctuation or optical peak power. Laser pulse energy separates these observables.

A finite optical record can bound later radiant energy if an independently justified exponential decay envelope applies at every later time. Let the recorded window end at $b$, and suppose the true nonnegative radiant power satisfiesIntegration gives the exponential-envelope tail-energy boundEquality holds when the entire tail follows the envelope. This is a bound on an unobserved contribution, not automatically a standard uncertainty or a probabilistic interval.

For an original numerical example, suppose the energy inside the recorded window is known to lie in $[48,52]\mathrm{nJ}$, while a justified envelope has $A=0.20\mathrm{W}$ and $\tau =20\mathrm{ns}$. The missing contribution is at most $4\mathrm{nJ}$, so the total laser pulse energy lies in $[48,56]\mathrm{nJ}$. The optical energy outside a time gate fraction, considering only this late contribution, is at most $4/(48+4)\approx 7.69\%$. Any unobserved early energy requires its own bound.

One way to justify the envelope mathematically is a differential inequality for an exponential tail envelope. Suppose $P$ is absolutely continuous on each finite interval after $b$, $P(b)\le A$, and $P^{\prime }(t)\le -P(t)/\tau$ almost everywhere. Multiplying by the integrating factor $e^{(t-b)/\tau }$ givesso $e^{(t-b)/\tau }P(t)\le P(b)\le A$. The decay law must apply throughout the unobserved region; it is a physical assumption to validate, rather than a consequence of fitting the last few samples.

The distinction is testable by a counterexample. Append a later nonnegative pulse whose support lies entirely beyond the recorded interval. Its energy can be arbitrarily large while every recorded sample is unchanged. Such a pulse violates the global envelope but cannot be excluded by a good local exponential fit alone. Similarly, an envelope $A{e}^{-(t-b)/\tau }+P_0$ with a positive constant background $P_0$ has an infinite integral over an infinite time interval. A finite observation horizon or an adequately defined and validated background subtraction is then essential.

Uncertain envelope parameters require a bound valid for their allowed combinations. If the allowed set is the rectangle $0\le A\le A_{\max }$ and $0<\tau \le {\tau }_{\max }$, then $U_{\mathrm{tail}}\le A_{\max }{\tau }_{\max }$. For $A_{\max }=0.25\mathrm{W}$ and ${\tau }_{\max }=25\mathrm{ns}$, this is $6.25\mathrm{nJ}$ and the preceding total interval becomes $[48,58.25]\mathrm{nJ}$. More restrictive joint parameter constraints can tighten this result; inserting separate best-fit values does not establish a guaranteed bound.

Finally, an electrical tail need not be an optical tail. In an original idealized linear time-invariant system, let a photodetector have unit-area impulse response $h(t)={\tau }_d^{-1}{e}^{-t/{\tau }_d}$ for $t\ge 0$, and zero otherwise. An impulsive optical input $U\delta (t)$, with $\delta$ the Dirac delta function, gives the calibrated output $s(t)=Uh(t)$ by convolution. Its electrical tail after $L$ has area $U{e}^{-L/{\tau }_d}$ even though all incident optical energy arrived at time zero. This optical tail and detector-response ambiguity requires a separate response measurement. NIST's historical procedure characterized the photodetector, cable and oscilloscope together before convolving measured responses with trial waveforms. Appendix C describes typical optical excitation of about $120\mathrm{ps}$, a photodetector rise time near $5\mathrm{ns}$, and a $1\mathrm{GHz}$ oscilloscope with $0.4\mathrm{ns}$ rise time. The optical excitation was much shorter than the detector response, while the oscilloscope was fast enough that the detector dominated the measured waveform. Response data were collected at each gain setting and several signal levels.^[ref]

Colin Danson is a laser physicist whose research concerns ultra-high-power laser development and applications. His Oxford profile identifies this research portfolio and his work with the Oxford Centre for High Energy Density Science.^[ref]

Danson coauthored the1999 Central Laser Facility report on single-shot third-order intensity autocorrelation measurements.^[ref] Characterizing optical pulse temporal contrast matters because a large peak power does not describe all the energy arriving before or after the main pulse.

For an original rectangular-pulse example,20joules delivered in1picosecond givesA feature at one thousandth of that power still has20gigawatts. The ratio is small while the absolute power is large. Neither number alone specifies the feature's energy, which also depends on its duration.

Real pulse profiles require the integral $E=\int P(t)dt$ rather than assuming a rectangular shape. A diagnostic must therefore connect laser pulse energy, pulse duration and contrast with the actual temporal waveform. The example illustrates that measurement problem; its numbers are not historical Vulcan specifications.

A raw laser pulse energy estimate and its baseline correction can contain the same readout error. Let $Y$ be the raw gate integral, $B$ the estimated integrated background and $\hat{U}=Y-B$ the corrected result. Linearity of covariance gives the exact identityFor this linear measurement model, the law of propagation of uncertainty is exact whenever the input variances exist. Its general form includes the sensitivity coefficients and covariance terms.^[ref] Positive covariance reduces the variance of this difference; it would instead increase the variance of a sum.

An original shared-offset model makes the mechanism explicit. For fixed gate duration $T$, writewhere $c$ is a common additive power-readout offset with standard uncertainty ${\sigma }_c$, while ${\epsilon }_Y$ and ${\epsilon }_B$ are independent zero-mean energy errors, independent also of $c$. Then $\mathrm{Cov}(Y,B)=T^2{\sigma }_c^2$, and shared-offset cancellation in a baseline-corrected pulse integral gives $\hat{U}=U+{\epsilon }_Y-{\epsilon }_B$. The shared offset contributes no uncertainty to this difference. It need not be small or separately known.

Choose $T=10\mu \mathrm{s}$, ${\sigma }_c=0.20\mathrm{mW}$, $u({\epsilon }_Y)=0.30\mathrm{nJ}$ and $u({\epsilon }_B)=0.40\mathrm{nJ}$. The shared energy contribution is $2.0\mathrm{nJ}$ in each reading. Thus $u^2(Y)=4.09{\mathrm{nJ}}^2$, $u^2(B)=4.16{\mathrm{nJ}}^2$ and $\mathrm{Cov}(Y,B)=4.00{\mathrm{nJ}}^2$, yielding $u(\hat{U})=0.50\mathrm{nJ}$. Incorrectly discarding the covariance gives $\sqrt{8.25}\approx 2.87\mathrm{nJ}$.

Cancellation weakens if the offset changes between acquisitions. Replace $c$ by two offsets with the same standard uncertainty ${\sigma }_c$ and correlation coefficient $\rho$. Under the same independent residual-error assumptions,At $\rho =0.90$, the chosen example gives $u(\hat{U})=\sqrt{1.05}\approx 1.025\mathrm{nJ}$. A baseline taken far away in time cannot simply be assigned the covariance of an unchanged offset.

A sampled implementation has the same structure. If a vector of readings $\mathbf{x}$ has covariance matrix $C$, and fixed integration weights give $Y={\mathbf{q}}^T\mathbf{x}$ and $B={\mathbf{w}}^T\mathbf{x}$, thenA constant offset cancels when the weights sum to the same gate duration: ${\mathbf{q}}^{T}1={\mathbf{w}}^{T}1=T$. This does not justify using pulse-contaminated readings as background. Matched blank sequences, collected with the actual timing, help characterize the needed noise correlations.

The historical NIST TC-24 apparatus used a thermocouple-based absorbing plate and averaged baseline measurements before and after laser injection to compensate background and thermal drift.^[ref] The offset model above is an independent illustration, not a reconstruction of that instrument's uncertainty budget.

Cristina Hernandez-Gomez develops high-power laser technology and experimental facilities. Her Central Laser Facility biography describes work on the Vulcan Petawatt upgrade after joining in1997, followed by leadership of Vulcan and the High Power Lasers Division.^[ref]

She coauthored the1999 single-shot pulse-correlation report with the other Central Laser Facility researchers listed in its byline.^[ref] The diagnostic problem includes distinguishing a weak, extended signal from the main short pulse.

An original rectangular-waveform example separates peak contrast from energy contrast. Let the main pulse have power $P_0$ for1picosecond and a preceding feature have power $10^{-4}{P}_0$ for100picoseconds. Their energy ratio isThe preceding feature is at0.01% of the main peak, yet contains1% of the main pulse energy in this stipulated model. Reporting only its height would conceal its much longer duration.

This is why optical pulse temporal contrast and laser pulse energy need temporal definitions and a measured waveform. Facility development involves controlling the delivered pulse as well as its nominal peak: the diagnostic should establish what reaches the experiment, over the time interval relevant to that experiment.

The encircled radiant energy of a Gaussian beam is the radiant energy inside a centred circular receiver at a specified transverse plane. For fixed Gaussian beam radius $w$ and total laser pulse energy $U$,The radiant exposure of a Gaussian beam contains the radial integration and aperture-capture plot. Its $w$ is the irradiance $e^{-2}$ radius, as specified in the primary beam account.^[ref]

An original annular example distinguishes energy near an axis from energy between two radii. Subtracting two encircled values givesChoose $U=5\mu \mathrm{J}$, $w=0.50\mathrm{mm}$, $R_1=0.25\mathrm{mm}$ and $R_2=0.50\mathrm{mm}$. The annulus receives $5(e^{-1/2}-e^{-2})\approx 2.356\mu \mathrm{J}$, or 47.12 percent of the full beam energy. A bright central point does not imply that most energy lies in an arbitrarily small disk around it.

Indeed, the radial radiant-energy density of a Gaussian beam is $dQ/dR=2\pi RH(R)$, where $H$ is local radiant exposure. For this profile it is largest at $R=w/2$, even though $H$ is largest at zero radius. Increasing a centred aperture and comparing integrated detector readings can test the cumulative prediction. Detector linearity, aperture alignment and the finite collection boundary must be controlled; a displaced aperture is not described by the centred formula.

An energy-normalized pulse profile separates an optical pulse's temporal shape from its total laser pulse energy. For nonnegative radiant power $P(t)$ and finite $U=\int P(t)dt>0$, define $p(t)=P(t)/U$. Then $p$ has units inverse time and integrates to one. The radiant energy in a time interval is $U$ times the integral of $p$ over that interval.^[ref]

For an original two-lobe example, let $p=1/(8\mathrm{ns})$ during $0<t<2\mathrm{ns}$ and $p=3/(8\mathrm{ns})$ during $5<t<7\mathrm{ns}$, with zero values elsewhere. The two integrals are $1/4$ and $3/4$. Choosing $U=4\mathrm{nJ}$ gives powers $0.5$ and $1.5\mathrm{W}$, and energies $1$ and $3\mathrm{nJ}$. Multiplying $U$ by two doubles both powers without changing $p$.

The temporal energy centroid of an optical pulse is $\int tp(t)dt$ when this moment exists. Here it is $(1/4)(1)+(3/4)(6)=4.75\mathrm{ns}$, in the gap between lobes. An energy centroid need not be a location of maximum power.

Mathematically, $p$ is a probability density function, but its weighting here is energy over time. It is not automatically a measured photon-arrival distribution, particularly when photon energies vary. A zero-energy trace cannot be normalized this way, and a noisy baseline-corrected trace with negative excursions is not automatically a nonnegative density. The Gaussian pulse energy and peak power article gives one normalized shape family.

For an isolated Gaussian pulse, the relation between laser pulse energy $U$ and peak power $P_{\mathrm{pk}}$ depends on the pulse-width convention. Here $P(t)$ is the total incident radiant power, the background is zero, and $\tau >0$ denotes the power full width at half maximum. Integrating $P$ over the entire pulse defines its positive energy $U>0$.

Pulse energy, peak power and average power resolve different information. Consider a Gaussian pulse withThe chosen pulse duration $\tau$ is the full width at half maximum of radiant power: $P(\pm \tau /2)=P_{\mathrm{pk}}/2$. It refers to radiant power, rather than the wave amplitude of the electric field. The Gaussian integral gives the relation between Gaussian pulse energy and peak power:The pulse energy shape factor is $\kappa =U/(P_{\mathrm{pk}}\tau )$. It equals $1.064467$ for this power profile; a rectangular pulse of duration $\tau$ has $\kappa =1$. Knowing only a width and an integrated energy therefore requires a pulse-shape assumption before inferring peak power.

An equivalent form makes the normalization transparent. Write the pulse centre as $t_0$, and let $\sigma$ denote the standard deviation of its energy-normalized pulse profile:The ratio $p(t)=P(t)/U$ is a probability density function in the mathematical sense: it is nonnegative, has units ${\mathrm{s}}^{-1}$, and integrates to one. Here it weights the pulse's energy over time. Its normal distribution profile has mean $t_0$ and variance ${\sigma }^2$. This gives $P_{\mathrm{pk}}=U/(\sqrt{2\pi }\sigma )$ without a separate area estimate.

For a stipulated $\sigma =2\mathrm{ns}$ and $U=1\mathrm{nJ}$, the power full width at half maximum is $4.70964\mathrm{ns}$ and the peak power is $0.19947\mathrm{W}$. Confusing the standard deviation with the full width at half maximum would insert the wrong duration into the conversion.

The Gaussian pulse field-envelope width is a second distinct convention. If a fixed spatial field profile gives $P(t)=K|A(t){|}^2$ for a constant $K>0$, the wave amplitude envelope obeysConsequently its amplitude full width at half maximum is ${\tau }_E=\sqrt{2}\tau$. Inserting ${\tau }_E$ into the formula for a power-width input underestimates the true peak power by a factor $1/\sqrt{2}$. State which measured waveform defines the width.

An electrical photodetector trace can also be broadened by its impulse response. The optical pulse-width inference therefore needs a characterized detector response.^[ref]

The Gaussian pulse time-gate energy fraction is the share of an isolated pulse's laser pulse energy admitted by a finite time window. The result below acts on incident optical radiant power. Let $\tau$ be the power full width at half maximum, and first place the pulse centre and the detection time gate centre at zero.

A detection time gate need not collect the whole pulse. Integrating the same profile only over $-T_g/2\le t\le T_g/2$ gives the Gaussian pulse time-gate energy fractionwhere $\mathrm{erf}$ is the error function. A gate as wide as the power full width at half maximum collects only $\mathrm{erf}(\sqrt{\ln 2})\simeq 0.760968$, or 76.10% of the pulse energy. The pulse has nonzero Gaussian tails outside that interval. A real readout's impulse response can extend the required integration window further.

Alignment adds a parameter. Let the pulse centre be $t_0$, the gate centre be $t_c$, and write the Gaussian gate centring error as $d=t_c-t_0$. Put $\sigma =\tau /(2\sqrt{2\ln 2})$. Integrating the normalized Gaussian pulse profile over the gate givesAt $d=0$ the two error function terms reduce to the centred formula above. With $T_g=\tau$ and $d=\tau /2$, the captured fraction drops to $0.490734$. The pulse centre then lies on a gate edge. Merely keeping the gate width fixed does not keep its collected energy fixed.

The gate works best when centred. With the centred energy-normalized pulse profile $p(s)=P(t_0+s)/U$ and $a=T_g/2$, differentiation of $F(d)={\int }_{d-a}^{d+a}p(s)ds$ givesA Gaussian function is an even function about its centre and decreases with distance from that centre. Thus $F^{\prime }(d)\le 0$ for $d>0$, and symmetry gives the opposite sign for $d<0$. The same argument proves that a centred interval maximizes mass for an even unimodal density; unimodality supplies the required monotonicity.

A centred gate of width $2\tau$ captures $0.981468$ of the energy. Solving $\mathrm{erf}(\sqrt{\ln 2}{T}_g/\tau )=0.99$ gives $T_g\simeq 2.18771\tau$ for 99% capture in this ideal model. The requirement changes if the centring error is nonzero.

Pulse timing jitter can therefore create variation in gated energy even when every full pulse has the same $U$. A wider gate reduces this loss but also changes admitted background and the chance of including neighbouring pulses. Measure the timing and detector response associated with the chosen gate.

For a detector modeled as a linear time-invariant system, its recorded waveform is a convolution of the optical input with its impulse response. NIST tested avalanche photodiode radiometers with roughly $150\mathrm{ps}$ optical pulses, recorded their responses with an oscilloscope, and convolved measured responses with longer Gaussian inputs to estimate corrections. The detector and amplifier were characterized together.^[ref] A gate applied to that electrical waveform must use the readout model rather than assuming the optical fraction is unchanged.

Laser pulse energy is the radiant energy carried by one specified laser pulse across a measurement plane. For an isolated pulse whose total radiant power is $P(t)\ge 0$ and whose background is zero,Here $P$ is already integrated over the transverse beam area; it is not local irradiance. The unit of $U$ is the joule. Radiant exposure instead divides received energy by a receiving area, so a beam's $U$ alone does not specify the exposure at its centre. The radiant exposure of a Gaussian beam makes that spatial distinction quantitative.

The Gaussian pulse energy and peak power relation gives $P_{\mathrm{pk}}\simeq 0.939437U/\tau$ when $\tau$ is the power full width at half maximum. The pulse energy shape factor records pulse-shape dependence, while the Gaussian pulse field-envelope width is $\sqrt{2}$ times the power width.

For an original example, stipulate $U=0.50\mu \mathrm{J}$ and a Gaussian pulse power full width at half maximum $\tau =10\mathrm{ns}$. Then $P_{\mathrm{pk}}=46.97\mathrm{W}$. Stretching the same model pulse to $40\mathrm{ns}$ while keeping $U$ unchanged reduces its peak power to $11.74\mathrm{W}$. Both curves below integrate to the same energy; their peak heights and widths differ.

A finite detection time gate collects the Gaussian pulse time-gate energy fraction, which depends on its width and alignment. A centred gate as wide as the power full width at half maximum receives only $76.10\%$ of $U$, because Gaussian tails extend beyond it. For a $\tau$-wide gate, a Gaussian gate centring error of $\tau /2$ reduces capture to $49.07\%$.

The average power of a laser pulse train follows by counting complete pulses. If a long observation of duration $T$ contains $N$ pulses of energies $U_1,\dots ,U_N$, with negligible edge contributions and no continuous background,Here $f_{\mathrm{rep}}$ is the pulse repetition frequency, not the inverse pulse width. An average power readout constrains $\overline{U}$ when $f_{\mathrm{rep}}$ is known; it does not resolve pulse-to-pulse energy fluctuation. Identical, well-separated $0.50\mu \mathrm{J}$ pulses at $1.0\mathrm{MHz}$ give $0.50\mathrm{W}$ average power, even though the stipulated $10\mathrm{ns}$ pulses peak near $47\mathrm{W}$.

If a steady optical background is present, state whether the reported energy includes it. For pulse energy above a measured background $P_{\mathrm{bg}}$, the pulse energy baseline correction uses ${\int }_{\mathrm{gate}}[P(t)-P_{\mathrm{bg}}]dt$. Failing to subtract a constant background adds $P_{\mathrm{bg}}{T}_g$ to the inferred energy. This optical-background model is distinct from an offset introduced later by detector electronics.

Historical NIST equipment illustrates what the readouts measure. Its TC-24 reference absorbed the beam in a glass plate, sensed a plate temperature difference with thermocouples, and integrated the thermopile's electric potential difference during beam injection. Before/after readings enabled background subtraction and compensated thermal drift. Counting pulses converted total injected energy to mean pulse energy. The semiconductor pulse photodetector used an integrating amplifier; calibration related the peak output electric potential difference to pulse energy. That electrical peak did not by itself establish optical peak power.^[ref] Pulse energy measurement with a photodiode connects this kind of measurement to collected electric charge; validating the detector response under the actual pulse conditions remains part of that interpretation.

An optical postpulse is a secondary optical pulse arriving after the chosen main pulse. Specify the delay, relative peak radiant power, duration and collected laser pulse energy: a relative peak alone does not determine the energy of a differently shaped replica. It is distinct from an extended optical pulse pedestal and from electronic ringing from a photodetector.

A transparent plate provides a concrete mechanism. At normal incidence, a transmitted replica that makes one additional internal round trip has approximate delaywhere $\ell$ is plate thickness and $n_g$ is its group refractive index. Neglect absorption, dispersion and overlap, and let each internal reflection retain power fraction $R$. The first delayed replica then has approximately $R^2$ times the directly transmitted energy. This etalon round-trip delay can create a physical optical echo.

For an original chosen $\ell =1.2\mathrm{mm}$, $n_g=1.5$ and $R=0.04$, the delay is about $12\mathrm{ps}$ and the energy ratio is $0.0016$. A $2.0\mathrm{mJ}$ main pulse would be followed by a $3.2\mu \mathrm{J}$ replica under that model. The historical single-shot correlator experiment deliberately inserted a BK7 etalon to generate and detect such a delayed pulse.^[ref]

Changing the plate thickness tests the delay prediction; changing optical alignment tests whether a stray reflection is involved. A third-order intensity autocorrelation can distinguish temporal sides under its model, while a symmetric second-order intensity autocorrelation cannot alone assign a feature to a prepulse or postpulse. An opposite-delay correlation feature may instead be a third-order pulse correlation ghost; it need not identify another physical pulse.

An optical prepulse is a secondary optical pulse arriving before the reference main pulse. The sign of its delay is part of the definition: choose the main pulse at $t=0$, so a prepulse has negative arrival time. A weak earlier pulse and an equally weak optical postpulse can affect a target differently when the material retains a response to the earlier illumination. Temporal order therefore carries information that one total laser pulse energy does not.

An original separated rectangular-profile example uses a main pulse of duration $100\mathrm{fs}$ and a prepulse of duration $10\mathrm{ps}$ centred $50\mathrm{ps}$ earlier. Let the prepulse's peak radiant power be $10^{-4}$ of the main peak. The optical pulse temporal contrast is $10^4$, but the energy ratio isThus the prepulse carries $1/101\approx 0.990\%$ of the two-pulse energy. If the main pulse carries $1\mathrm{mJ}$, the prepulse carries $10\mu \mathrm{J}$. These stipulated disjoint power profiles have no field-overlap term, and the main pulse's full width at half maximum does not reveal the earlier contribution.

A temporal diagnostic needs both sufficient delay coverage and calibrated dynamic range. The single-shot third-order correlator paper motivates its asymmetric response by contrasting it with the symmetric second-order trace, which loses the distinction between before and after.^[ref] Its delay axis still needs a known physical reference. A third-order pulse correlation ghost from a real postpulse can appear on the prepulse side; interpreting every small lobe as earlier light would be incorrect.

Repeating the measurement while varying an independently characterized optical delay helps assign temporal order. Record the detector baseline subtraction, coverage and response width along with the trace. A nondetection means a limit within those measurement conditions, rather than proof of zero early optical energy.

An optical pulse pedestal is lower-level optical power extending around a pulse's dominant short peak. It can precede the peak, follow it or extend on both sides. A broad pedestal can carry substantial laser pulse energy while barely changing the peak's full width at half maximum. Optical pulse temporal contrast describes the relative power levels; integrated energy also depends on how long each contribution persists.

For an original power-profile model, choose a central rectangular contribution of height $P_0$ and duration $\tau$, together with a pedestal of height $\alpha P_0$ and duration $T>\tau$, centred at the same time. Let $0<\alpha <1$. The peak power is $(1+\alpha )P_0$, while the pedestal lies below half of that value. The power FWHM is therefore still $\tau$, butThese are stipulated additive power contributions, not a rule for adding coherent electric fields.

Set $\alpha =10^{-3}$ and $T=1000\tau$. The pedestal then contains half the total energy even though its power is about a thousand times below the main peak. With $P_0=1\mathrm{MW}$ and $\tau =1\mathrm{ps}$, each contribution carries $1\mu \mathrm{J}$. The peak-to-pedestal power ratio is exactly $(1+\alpha )/\alpha =1001$ in this example. An inverse convention would quote a small pedestal-to-peak ratio instead; state which contrast definition is being used.

A measurement needs temporal range as well as dynamic range. A narrow scan can miss broad wings, while a readout that resolves only the peak can bury a pedestal in its own background. A commercial example is the Sequoia third-order cross-correlation instrument, whose manufacturer identifies temporal-contrast measurement as its purpose and separately specifies scan range and temporal resolution.^[ref] The cited instrument description establishes the measurement approach; the numerical profile above is an independent model.

A real optical pedestal must also be distinguished from detector baseline subtraction errors. Blocked-beam and reference measurements characterize the detector background, while a suitable optical measurement tests whether low-level light accompanies the pulse. A detection time gate that excludes a pedestal changes the admitted energy relative to a detector integrating the full waveform.

Optical pulse temporal contrast compares a pulse's peak with weaker light at another time. For a radiant power trace with peak $P_{\max }>0$, explicitly choose either the peak-to-local ratio $C(t)=P_{\max }/P(t)$ or its inverse $r(t)=P(t)/P_{\max }$. The first is at least one where the local power is positive; the second lies between zero and one. With a fixed transverse beam shape, the same ratio can be formed from light intensity. If the beam shape changes with time, specify the spatial sampling instead of identifying local intensity and total power.

A plateau at $10^{-3}$ of the peak has $r=10^{-3}$ and $C=1000$. Expressing this power ratio as optical contrast in decibels givesFor an amplitude ratio $A$ whose power ratio is $A^2$, the same definition gives $10{\log }_{10}(A^2)=20{\log }_{10}A$. Contrast also needs a delay or time range: an optical prepulse, an optical postpulse and a long optical pulse pedestal can have the same relative height but different positions and laser pulse energies. The pedestal energy fraction additionally requires integration over the contribution's duration.

A useful nonlinear measurement is third-order intensity autocorrelation. In an ideal instantaneous model, an input light intensity $I(t)$ generates a second-harmonic gate proportional to $I^2(t)$. Sum-frequency generation with a delayed fundamental replica gives a recorded signal proportional toThe instrument measures this cross-correlation, rather than simply reading $I(\tau )$. Finite gate width, phase matching, spatial overlap and detector response enter the interpretation.

The1998/99 instrument of J. Collier and colleagues used second-harmonic generation, a Wollaston prism and an optical biprism to form crossing fundamental and harmonic beams. A second crystal generated the sum-frequency signal, imaged through optical filters onto a charge-coupled device. Position encoded delay. An inserted glass etalon produced a delayed replica near $1.5\times 10^{-3}$ of the main signal, recorded on one side of the correlation peak. Figure4 combines window settings shifted with etalons.^[ref]

An independent ideal calculation explains both the asymmetry and a possible third-order pulse correlation ghost. Let $I(t)=g(t)+\epsilon g(t-d)$ represent two identical-shape pulses with well-separated supports and correlation lobes, with the second weaker and delayed. Squaring introduces no overlap term. If $A_g(\tau )=\int g^2(t)g(t+\tau )dt$, expansion givesThe delayed replica produces a lobe of relative order $\epsilon$, while the opposite-delay ghost has order ${\epsilon }^2$. For $\epsilon =0.01$, the scales are about $10^{-2}$ and $10^{-4}$ respectively. These values are predictions of the stated ideal model. Assigning every small correlation feature directly to a separate input pulse would miss this distinction.

A nondetection below the measurement floor establishes a bound under a detection model, rather than demonstrating that no light exists there. Finite dynamic range, detector baseline subtraction, delay coverage and resolution should accompany a reported contrast trace. The Sequoia manufacturer likewise distinguishes optical temporal resolution from the scan step; making that step smaller does not alone narrow the optical response.^[ref]

The pedestal energy fraction is the fraction of an optical pulse's laser pulse energy assigned to its optical pulse pedestal. Specify the decomposition and integration interval before quoting it. For a nonnegative additive radiant power model $P(t)=P_m(t)+P_p(t)$,The assumptions $0\le P_p\le P$ imply $0\le f_p\le 1$ by integration. A pedestal fit is a model of the measured radiant power; it is not automatically a unique physical separation into optical fields. Overlapping fields with optical coherence can have wave interference terms, so their separate field energies cannot generally be added as though those terms were absent.

The distinction from optical pulse temporal contrast is quantitative. Use the stipulated rectangular model of optical pulse pedestal: a main contribution has height $P_0$ and duration $\tau$, while a centered pedestal has height $\alpha P_0$ and duration $T\ge \tau$. For $0<\alpha <1$, the total peak is $(1+\alpha )P_0$ and the power full width at half maximum remains $\tau$. Define peak-to-pedestal contrast $C=(1+\alpha )/\alpha$. ThenHalf the laser pulse energy is in the modeled pedestal when $T=(C-1)\tau$. A large peak-to-pedestal ratio therefore does not by itself imply a small energy contribution.

For an original comparison, fix $C=1001$ and the same $P_0,\tau$ in both traces. With $T=10\tau$, the pedestal fraction is $10/1010\approx 0.00990$; with $T=1000\tau$, it is $1/2$. Thus the same contrast and power FWHM can coexist with about1% or50% pedestal energy. At fixed finite $C$, increasing the pedestal duration can make $f_p$ approach one without changing that FWHM.

Optical energy outside a time gate is a related observable that avoids assigning a pedestal underneath the main peak. For a specified gate $G$ containing that peak,In the rectangular example with $G$ equal to the main interval, $f_{\mathrm{out}}=\alpha (T-\tau )/(\tau +\alpha T)$. At $\alpha =10^{-3}$ and $T=1000\tau$, this is $0.4995$, while $f_p=0.5000$. The difference is pedestal power inside the gate, which the outside-gate measurement does not label separately.

The analysis must also specify its temporal coverage and detector baseline subtraction. Subtracting actual weak light as though it were detector background changes the inferred laser pulse energy. A short detection time gate omits outlying light instead. Neither operation is justified solely by knowing the peak-to-pedestal contrast. The Sequoia technical sheet illustrates why temporal coverage and resolving power are separate instrument properties: it lists scan range, scan resolution and optical temporal resolution independently.^[ref]

Pulse-energy bounds from tail duration and pedestal height convert independently justified constraints on low-level light into a bound on total laser pulse energy. Peak power and full width at half maximum alone do not constrain an arbitrarily long below-threshold tail, as unbounded pulse energy at fixed peak and FWHM demonstrates.

Consider a nonnegative isolated power profile with peak $P$, one contiguous half-maximum interval of duration $\tau$, and total support of duration at most $D_{\max }\ge \tau$. Suppose power outside that interval is at most $H<P/2$. ThenThe lower bound uses the half-maximum condition within the interval. The upper bound fills that interval to $P$ and every permitted remaining instant to $H$. These bounds assume the stated shape class; multiple half-maximum crossings require an explicit interval convention.

For an original $P=8\mathrm{W}$, $\tau =5\mathrm{ns}$, $H=0.40\mathrm{W}$ and $D_{\max }=30\mathrm{ns}$, they give $20\le U\le 50\mathrm{nJ}$. Suppose a calibrated measurement additionally determines core energy $U_c=32\mathrm{nJ}$. The pulse-energy interval from incomplete tail measurements tightens towith the displayed product using watts and nanoseconds. Reducing the independently established tail duration to $15\mathrm{ns}$ tightens the upper bound to $36\mathrm{nJ}$ without changing the measured peak or width.

A receiver with characterized low-level response and a sufficiently long acquisition window is needed to justify $H$ and $D_{\max }$. A trace that falls below a detector threshold establishes no later support cutoff by itself. NIST's pulse-energy calibration discussion separates temporal waveform measurement from background and leakage effects.^[ref] The numerical bounds above are conditional mathematical examples, not specifications of that apparatus.

Pulse energy measurement with a photodiode estimates incident laser pulse energy from collected signal electric charge. At fixed wavelength, suppose a photodiode has constant calibrated spectral responsivity $R$ in amperes per watt and remains in its linear operating range. If $P(t)$ is the incident radiant flux, the signal photocurrent is $i_{\mathrm{sig}}(t)=RP(t)$. Integrating over the complete response givesThe units agree because amperes per watt equal coulombs per joule. Spectral responsivity must apply at the measurement wavelength; a broadband pulse requires accounting for its spectrum.

In an original example, let $R=0.40\mathrm{A}{\mathrm{W}}^{-1}$ and let the baseline-corrected collected charge be $Q_{\mathrm{sig}}=12\mathrm{nC}$. Then $U=30\mathrm{nJ}$. An ideal charge amplifier with feedback capacitance $C_f=100\mathrm{nF}$ would produce an output change of magnitude $Q_{\mathrm{sig}}/C_f=0.12\mathrm{V}$. The amplifier's polarity depends on its circuit convention.

A practical apparatus needs a calibrated detector, a charge-sensitive readout and a measurement window containing the full response. Detector baseline subtraction removes the estimated background, including dark current. A residual constant current of1microampere integrated over10microseconds contributes10picocoulombs; with the example responsivity this is a25picojoule energy error. Extending the window can capture a missing signal tail but also accumulate more background error.

Photodiode saturation invalidates the assumed constant response. Robert E. Vest and collaborators measured pulsed silicon-detector behavior and reported dependencies on applied reverse bias and illuminated area.^[ref] A low average optical power therefore does not by itself establish linear response to individual pulses.

Rodney W. Leonhardt's calibration report describes a complementary reference method: a slow thermal standard measures accumulated energy, while pulse count and a calibrated beam splitter ratio determine average energy in the test beam.^[ref] This connects a fast photodiode readout to an energy reference without requiring the thermal standard to resolve every pulse.

Collected charge measures energy under the stated assumptions; it does not alone determine peak power. A flat30nanojoule pulse lasting100nanoseconds has power0.30watts, whereas a flat pulse of the same energy lasting1microsecond has power0.030watts. Those stipulated rectangular profiles illustrate why pulse shape and pulse duration are additional information.

The pulse energy shape factor is the dimensionless ratiowhere $U$ is laser pulse energy, $P_{\mathrm{pk}}$ is background-subtracted peak power and $\tau$ is a stated pulse duration. It belongs to the chosen profile and width convention. Here $\tau$ denotes the power full width at half maximum, the convention explicitly used by the primary source documentation.^[ref]

An original counterexample compares a rectangular pulse with a bilateral exponential pulse. Give both the same $P_{\mathrm{pk}}$ and power FWHM $\tau$. The rectangle is nonzero over a width $\tau$, so $U_{\mathrm{rect}}=P_{\mathrm{pk}}\tau$ and ${\kappa }_{\mathrm{rect}}=1$. Forthe half-maximum points are again $\pm \tau /2$, but integration of the two tails gives $U_{\exp }=P_{\mathrm{pk}}\tau /\ln 2$ and ${\kappa }_{\exp }=1/\ln 2\approx 1.4427$.

With $P_{\mathrm{pk}}=2\mathrm{W}$ and $\tau =5\mathrm{ns}$, the energies are $10$ and $14.43\mathrm{nJ}$. The same measured peak and FWHM therefore leave a 44.3 percent difference in this example. This nonuniqueness of pulse energy at fixed peak power and FWHM is a profile ambiguity, not an instrument-unit conversion.

The Gaussian pulse energy and peak power article gives the Gaussian-family relation. Reconstructing an arbitrary pulse's energy requires the full calibrated profile or an additional justified shape model; a width and peak alone cannot supply it.

Pulse-to-pulse energy fluctuation is variation in the laser pulse energy of successive emitted pulses. For a stationary population with finite variance, its standard deviation is ${\sigma }_U=\sqrt{\mathbb{E}[(U-\mathbb{E}U{)}^2]}$. A finite record supplies an estimate, whose convention should be stated rather than being confused with the uncertainty of the record's mean.

For an original four-pulse record, take measured energies $9,11,11,9\mu \mathrm{J}$. Their mean is $10\mu \mathrm{J}$. The sample standard deviation isIts coefficient of variation is 11.55 percent. The root-mean-square deviation of this particular list, using divisor four rather than three, is instead $1\mu \mathrm{J}$ or 10 percent. The definition matters when comparing reported stability figures. The familiar $s_U/\sqrt{N}$ estimate of uncertainty in a mean additionally assumes independent, identically distributed observations; an ordered record alone does not establish that assumption.

A historical NIST stability assessment compared an internal excimer-laser pulse monitor with a pyroelectric laser-energy meter. Its calorimeter integrated a pulse train, so averaging and individual-pulse variation entered different parts of the analysis.^[ref]

Observed variability also includes readout noise. Separating detector noise from pulse-energy variance requires an appropriate measurement model and independent information about that noise. Detector saturation, drift and correlated pulse errors are not removed merely by collecting a longer record. An average power of a laser pulse train measurement by itself does not resolve this sequence.