Past exam of the mathematics course of the University of Cambridge 2024 iii Paper 309 1 a ii Solution Created 2026-09-24 Updated 2026-09-25
Write and . Varying with fixed endpoints and then choosing proper time as parameter, for which , gives the Euler-Lagrange equationExpanding the derivative, raising the free index with the inverse metric, and using the symmetry of gives the geodesic equationThese are the Christoffel symbols of the Levi-Civita connection.
Past exam of the mathematics course of the University of Cambridge 2025 ib Paper 1 2F Solution Created 2026-09-23 Updated 2026-09-25
In local coordinates with metric , the energy isThe Euler–Lagrange equations are equivalentlywhere .
For the plane-section curve , constant speed gives . Both and the surface normal lie in , while is spanned by and that normal along the intersection. Hence is normal to the surface. Its tangential acceleration vanishes, which is the geodesic equation.
Past exam of the mathematics course of the University of Cambridge 2025 iii Paper 312 4 ii Solution Created 2026-09-24 Updated 2026-10-03
Divide the time component of the geodesic equation by and use . To first order, . Substitution of the supplied Christoffel symbols makes the background terms cancel the derivative of . The derivatives of the lapse and shift also combine, leavingThus the comoving photon energy is conserved in the unperturbed spacetime and changes through the gradient of the scalar gravitational source.
Past exam of the mathematics course of the University of Cambridge 2025 ii Paper 3 25I b ii Solution Created 2026-09-24 Updated 2026-09-25
A unit-speed surface curve is a geodesic when its acceleration is normal to the surface, equivalently when its covariant acceleration vanishes. In coordinates , the Christoffel symbols of the Levi-Civita connection areThe coordinate functions of a geodesic satisfy the geodesic equation
Past exam of the mathematics course of the University of Cambridge 2025 ii Paper 4 37E b Solution Created 2026-09-24 Updated 2026-09-25
For a slowly moving particle in a static weak field, the spatial part of the geodesic equation reduces toTo first order in the perturbation,and henceNewtonian acceleration is , so . Substitution into part (a), followed by the Poisson equation , givesThus the Newtonian limit of general relativity fixes
Past exam of the mathematics course of the University of Cambridge 2026 iii Paper 309 1 a Solution Created 2026-09-24 Updated 2026-09-25
A Killing vector field obeys , or equivalently . Along an affinely parametrized geodesic with tangent ,The second term vanishes by the geodesic equation, while the first contracts the symmetric tensor with the antisymmetric part selected by the Killing equation. Thus is a geodesic conserved quantity from a Killing vector. In Minkowski spacetime, translational Killing fields give conserved energy-momentum and rotational or boost Killing fields give the corresponding angular-momentum and boost charges; the same construction works for any spacetime isometry.
Past exam of the mathematics course of the University of Cambridge 2026 iii Paper 311 1 a i Solution Created 2026-09-24 Updated 2026-09-25
Because is a null tangent, metric compatibility givesBecause is tangent to an affinely parametrized null geodesic congruence,by the geodesic equation. Thus has no component along in either index.
Past exam of the philosophy of space-time course of the University of Oxford 2021 5 Solution 2026-10-25
The phrase equivalence principle covers several related claims. The weak equivalence principle concerns the universality of free fall for test particles of negligible self-gravity, with the same initial conditions and no relevant nongravitational forces. In a Newtonian notation,Composition-independent motion requires the ratio of passive gravitational mass to inertial mass to be universal. Its common value can then be absorbed into the normalization of ; the empirical assertion is universality, not the numerical convention used to express the ratio.
The Einstein equivalence principle includes that universality and extends the claim to local nongravitational experiments through local Lorentz invariance and local position invariance. A sufficiently small freely falling laboratory should recover the nongravitational laws of special relativity. The strong equivalence principle extends the scope to local gravitational experiments and bodies with appreciable gravitational self-energy. An experiment establishing one part of the weak statement does not automatically establish these stronger claims.
The motivating elevator comparison makes both the power and the limitation clear. Release a small object in a freely falling cabin. The cabin and object share the local free fall, so the object initially floats relative to the cabin. In a cabin supported against gravity, a released object instead accelerates relative to the floor, as it does in a suitably accelerated cabin in flat spacetime. This suggested replacing a universal gravitational force by geometric inertial motion. It does not identify a finite planetary gravitational field with an accelerated frame everywhere: separated falling objects can have a measurable relative acceleration.
In general relativity, the precise local geometric statement is that one can choose normal coordinates at an event withThis eliminates the connection contribution to the geodesic equation at that point. It does not generally set the Riemann curvature tensor to zero. In normal coordinates the first metric corrections away from are quadratic in the coordinate separation, and geodesic deviation measures the associated tidal forces. Equivalence is a local approximation for finite experiments whose extent and duration make these corrections negligible; it is not an assertion that curvature has been transformed away.[ref]
General Relativity by David Tong. sections 3.3.2 and 3.3.4: normal coordinates and geodesic deviation
There are direct experimental consequences beyond the elevator thought experiment. An Eötvös experiment compares bodies of different composition on a torsion balance, using a differential signal to test the universality of gravitational acceleration. MICROSCOPE performed an analogous test in orbit using electrostatic control of titanium-alloy and platinum-alloy test masses. Its first published result in 2017 constrained their differential free fall; this was already available before the examination. It tested a specific weak-equivalence prediction, not every possible gravitational law.[ref]
The MICROSCOPE mission: first results of a space test of the Equivalence Principle by Pierre Touboul and others. 2017 abstract and experimental description: composition comparison and differential control forces
Comparisons of different atomic clocks can instead test local position invariance, including the expected gravitational redshift. These measurements constrain related but distinct parts of the framework.The principle remains important as a restriction on how matter couples to gravity and as an organizing guide for experimental tests. It does not, on its own, derive the Einstein field equations. Universally coupling matter to a metric tensor still leaves choices for that metric's action; the equivalence principle does not uniquely fix field equations. For example, a metric gravitational action containing a scalar curvature squared term can retain the same minimal matter coupling while changing the gravitational dynamics. Selecting the Einstein-Hilbert action requires further dynamical assumptions and empirical success. The present role of the principle is consequently precise and limited: it supports local relativistic physics and universal matter coupling, while curvature, gravitational field equations and their quantitative predictions remain additional content.
The equivalence principle connects the universality of freely falling motion to the local description of gravity. In Newtonian language a test body's response to a given field is proportional to . Equality of that ratio for different non-gravitating test bodies gives the weak equivalence principle: identical initial conditions yield identical free-fall trajectories, independent of composition. Negligible nongravitational forces and negligible disturbance of the background are part of the test-body limit.
The Einstein equivalence principle adds local Lorentz invariance and local position invariance for nongravitational experiments. A sufficiently small freely falling laboratory obeys the local laws of special relativity independently of its spacetime location and freely falling velocity. Uniform acceleration of a small laboratory can imitate the leading local effects attributed to a gravitational field. An observer held at rest in a gravitational field generally needs proper acceleration; a freely falling observer does not.
Mathematically, local inertial coordinates can set the metric to Minkowski form and the Christoffel symbols to zero at an event. The geodesic equation there has no connection term at that point:This coordinate choice does not remove curvature. With a standard curvature convention, nearby free-fall trajectories have relative accelerationThe tidal signal survives in an extended laboratory. Thus the principle is local and does not identify every gravitational field with acceleration globally. Finite-size spin and tidal couplings also qualify the ideal point-test-body statement.
The strong equivalence principle extends the universality to gravitational experiments and bodies whose gravitational self-energy is important. It is stronger than the Einstein principle and need not hold in every metric theory that satisfies local nongravitational equivalence. Comparing the Earth and Moon as they fall toward the Sun probes this distinction as well as composition effects. Lunar laser-ranging analyses test differential acceleration by fitting the lunar orbit and measured ranges; an interpretation in terms of self-energy requires separating ordinary composition-dependent violations.[ref]
Lunar Laser Ranging Tests of the Equivalence Principle by James G. Williams and others. 2012 abstract, differential Earth-Moon free fall and dependence on composition and gravitational self-energy
Redshift and clock comparisons test local position invariance; laboratory Lorentz tests and universality-of-free-fall experiments test other components. These are complementary tests, not deductions from a single numerical equality of inertial and gravitational mass. The principle motivates geometric gravity and minimal coupling, but does not by itself derive the complete Einstein field equations or determine the value of the gravitational constant.
Past exam of the relativity course of the University of Cambridge 2012 Paper 1 4 Solution 2026-10-20
Put and let dots now denote an affine parameter derivative. The null geodesic lagrangian in the orbital plane is . The time and azimuthal Euler-Lagrange equations integrate once; the null normalization givesFor completeness, the differential radial geodesic equation isthe remaining differential equations are and . Spherical symmetry permits the equatorial choice.
Eliminating yields . For , divide by :The impact parameter is unchanged by a common rescaling of the affine parameter. At infinity it is times angular momentum divided by energy. Radial photons have and obey the undivided equation .
The effective potential is zero at , positive outside, and tends to zero as . Its derivative is . ThusThe circular null geodesic lies at a maximum, since . It is unstable: a small radial displacement away from the maximum permits motion away from the orbit. For incoming photons from infinity in the exterior of a black hole, an outer turning point exists when ; for the photon can cross the event horizon. For a material central body, the vacuum circular orbit is relevant only if lies outside its surface.
Photon potential and horizon-penetrating light cones
. Details. For the new coordinates, set , so . The geodesic Lagrangian is . Cyclic-coordinate conservation and the null condition give the required analogous equations:Here denotes the same conserved time-translation quantity as before. The transformation is . In particular, the displayed time coordinate belongs to Ingoing Kerr-Schild coordinates for Schwarzschild spacetime; the usual advanced null coordinate of ingoing Eddington-Finkelstein coordinates is . Using a metric tensor with a vanishing coefficient while retaining the name would therefore solve a different coordinate representation.
An elimination that stays finite at the horizon is especially simple:The middle equality uses . Hence the radial energy equation and are unchanged, including the horizon limit. The radial metric tensor block has determinant and is regular at . Its radial null directions are and , as shown in the original schematic.
This coordinate invariance of the Schwarzschild photon radial potential follows because the transformation changes the time slicing but preserves the areal radius and the stationary Killing vector field . Consequently the conserved Killing energy, angular momentum and impact parameter are the same. photon capture, the circular orbit and the radial turning points cannot depend on coordinate labels; coordinate velocities can.
Past exam of the relativity course of the University of Cambridge 2013 Paper 1 1 c Solution 2026-10-20
The Christoffel symbols of a spatially flat FLRW metric depend on the time-coordinate convention. Here is , not . For an affine parameter , take . Its Euler-Lagrange equations areComparison with the geodesic equation givesAll others vanish because is constant and there are no spatial metric tensor derivatives. The lower-index interchange is essential: the printed list specifies one member of each symmetric mixed pair. The factor of two in the spatial geodesic equation comes from those two members.
Past exam of the relativity course of the University of Cambridge 2014 Paper 1 4 Solution 2026-10-20
geodesic integrals and affine normalization. Put . Choose the affine parameter to be proper time, so . Cyclic and in the geodesic Lagrangian give and . Substituting into the four-velocity normalization giveshenceAn arbitrary constant rescaling of affine parameter changes its normalization; the displayed unit constant assumes the proper-time choice.
circular orbit. Define . The radial geodesic equation is . A circular geodesic therefore needs , not merely at an instant. Solving and substituting into the radial first integral givesExistence requires . circular orbits below are radially unstable, although they still define the instantaneous comparison here.
orthogonal local velocities in Schwarzschild spacetime. Use Alice's static orthonormal frame at the meeting event. Her proper clock is and tangential proper distance is . Bob's local tangential speed isCarol has and , because she starts from rest at infinity. The radial integral gives . Her static-frame radial speed is , and , soThis is inward radial motion, perpendicular to Bob's tangential motion in Alice's frame.
Special-relativistic consistency. Let Bob's tangential velocity in Alice's local frame be and Carol's inward radial speed be . A boost to Bob's frame gives Carol components and . ConsequentlyThus the three measured relative speeds agree with local Lorentz velocity addition. Ordinary Euclidean subtraction of the two velocity vectors would omit the transverse-velocity transformation.
Past exam of the relativity course of the University of Cambridge 2015 Paper 1 2 c Solution 2026-10-20
Ordinary component differences at neighboring points depend on how the local bases vary. The covariant derivative corrects for that variation:Each upper tensor index adds a connection term and each lower index subtracts one. A scalar has , while the derivative of a tensor transforms as a tensor with one additional covariant index. The Christoffel symbols themselves are not tensor components; their inhomogeneous transformation cancels that of the ordinary derivative.
For the Levi-Civita connection,These express metric compatibility and zero torsion. Along , parallel transport is the initial value problemIt preserves inner products for the Levi-Civita connection. Parallel transport of the tangent itself gives the affinely parametrized geodesic equation, .
Transport generally depends on the path. On a round sphere, transport a tangent vector around the triangle bounded by two meridians degrees apart and the intervening equatorial arc. All three sides are geodesics; the enclosed spherical area is . The returning vector is rotated by degrees, with sign set by traversal orientation. Locally this holonomy is controlled by curvature, even though the connection can be made zero at a single point. A vector can therefore have changing coordinate components while remaining parallel, and constant components do not generally mean parallel transport.
Original spherical-triangle transport: a tangent initially pointing along the first meridian returns rotated by ninety degrees
. Details. Past exam of the relativity course of the University of Cambridge 2016 Paper 1 4 Solution 2026-10-20
Take as particle proper time, dots as , and with . In the equatorial plane the geodesic Lagrangian isThe cyclic coordinates give and . Set the resulting constants to and respectively. The explicit second-order equations areThe polar equation is satisfied by , , consistently with spherical symmetry. The proper-time normalization supplies the third first integral:The normalization is ; it is distinct from choosing an arbitrary affine tangent's norm.
Stationarity and axial symmetry make the covariant time and azimuthal momenta constant. For physical momentum and coordinate in seconds, and . Thus is the conserved energy normalized at infinity and is the signed axial angular momentum. This is Killing energy with positive time signature; a convention with negative timelike norm uses the opposite contraction sign. The supplied covariant-momentum form of the geodesic equation makes these cyclic constants immediate, but its parametrization must be understood: for it is exactly as written. For physical , proper-time differentiation instead gives ; equivalently, the displayed mass-free form uses . This affine momentum normalization does not change either conservation law.
Multiply the normalization equation by and substitute the two cyclic integrals. Rearrangement gives the radial energy equationFor radial marginal escape and the future-directed constant is , because the speed at infinity vanishes. Choose the outward root:Hence the marginal escape geodesic in Schwarzschild spacetime hasThe constant has units of length to the power divided by time. This radius is an areal coordinate, not accumulated local proper distance.
A Schwarzschild static observer at exterior radius uses local radial rulers and a local clock . Therefore the local radial speed of a Schwarzschild geodesic isFor the marginal trajectory this givesIts equality to is particular to ; the local definition, rather than that accidental equality, is the required observer measurement. The Schwarzschild-coordinate velocity is instead .
For nonzero asymptotic speed , the same energy constant is . Combining the radial equation with the local-ruler relation gives radial Schwarzschild escape with asymptotic speedThe positive root describes the outward particle, at radii on its trajectory with . Independently, a static observer has four-velocity in these coordinates, giving relative Lorentz factor and the same speed. As it tends to ; for it gives the preceding result. Its limiting value approaches as , but that is a limit through exterior observers: no static timelike observer exists on or inside the horizon.
Past exam of the relativity course of the University of Cambridge 2018 Section B B3 i Solution 2026-10-18
The relativistic orbit-shape equation can be derived without dividing by at a turning point. Substitute the norm constraint into the radial geodesic equation to eliminate and . Using givesFor a massive particle with proper time as parameter, . Put , and use primes in this paragraph for derivatives with respect to . The constant specific angular momentum gives , so the chain rule yieldsSubstituting these expressions into the radial equation and dividing by for a nonradial orbit givesThe extra term is responsible for Schwarzschild perihelion precession. It vanishes in the Newtonian weak-field limit . The derivation uses a massive particle; for a null geodesic, and the constant on the right is absent.
Past exam of the relativity course of the University of Cambridge 2018 Section B B3 Solution 2026-10-18
Use the metric signature and abbreviate , with a length. Dots initially mean differentiation with respect to an affine parameter . The geodesic Lagrangian in the equatorial plane isThe planarity of geodesics in spherical symmetry permits this plane to be chosen. More explicitly, the full angular Euler-Lagrange equation is , so initial data , preserve it.
Both and are cyclic coordinates. Their Euler-Lagrange equations give conserved conjugate momenta and . Defining constants therefore givesThe corresponding second-order geodesic equations areand variation of givesThe geodesic Lagrangian has no explicit dependence. Its conserved Lagrangian energy function is , since it is quadratic in the tangent components. Thus twice this function is a constant:This is the constant squared tangent norm of an affinely parametrized geodesic.
For a massive particle choose , its proper time, and obtain . For a photon, the tangent is null and . A general rescaling of a massive particle's affine parameter rescales a positive ; the numerical value requires the proper time choice. With that choice, is signed specific angular momentum, of units , and is dimensionless conserved specific Killing energy. The time coordinate is normalized to proper time at infinity, so this is the particle's conserved energy referred to infinity. A photon's constants scale with the normalization of its null tangent; it has no rest frame or proper time parametrization.
Substitution of and into the norm gives the general radial first integralFor a massive particle this becomesAdopting the usual half-normalization for the effective potential for timelike Schwarzschild geodesics, defineAll terms have units , or energy per unit mass. The first two terms are the Newtonian gravitational and centrifugal contributions; the last is the relativistic correction.
A circular orbit requires both and . Differentiating at fixed givesThe radial first integral also givesFor the future-directed circular orbit at , these constants are , , and . ThereforeSince Schwarzschild time agrees with the clock time of a static observer at infinity, the intended infinity-referred tangential orbital speed isThis uses the circumferential areal radius with the clock at infinity; it is not a local measurement made at the orbit. A local static observer's clock instead has and measures . These two operationally different speeds explain the significance of the phrase “at infinity”.
The effective-potential stability of a circular orbit follows fromConsequently the orbit exists but is unstable to radial perturbations. The original plot below shows its position at a maximum, for .
For a weak-field elliptic orbit, the relativistic correction makes the direction of closest approach advance after each radial cycle. The derivations under i and ii below giveper orbit to first order, where is the semi-major axis and the orbital eccentricity. For Mercury, the additional Schwarzschild perihelion precession is approximately 43 arcseconds per century, over and above the much larger Newtonian precession produced primarily by other planets. It is the unexplained residual after those effects have been included that provides the classic quantitative test of general relativity; one should not identify the whole observed precession with this relativistic correction.[ref]
https://ntrs.nasa.gov/api/citations/20180000952/downloads/20180000952.pdf. PDF p. 2: planetary perturbations about 531.63 arcseconds per Julian century and additional relativistic precession about 42.98 arcseconds per Julian century
Past exam of the relativity course of the University of Cambridge 2018 Section B B4 Solution 2026-10-18
Local equivalence and tides. In Newtonian mechanics, inertial mass measures the response to a force, whereas passive gravitational mass couples to an imposed Newtonian gravitational field. A freely falling body obeysThe observed composition independence of free fall says that this ratio is universal. With a common choice of units it is one. This is the Newtonian content of the weak equivalence principle for test particles; it does not by itself specify all nongravitational physics.
The Einstein equivalence principle further says that local nongravitational experiments in a sufficiently small freely falling laboratory have the form predicted by special relativity, independently of the laboratory's location and motion. In such a local inertial frame, the metric tensor is locally the Minkowski metric and the Christoffel symbols vanish at the selected event. The strong equivalence principle extends the universality claim to local gravitational experiments and bodies with significant gravitational self-energy. None of these statements removes measurable tidal forces across a finite apparatus.
In an ideal small freely falling lift, a released ball initially floats relative to the cabin, because both undergo the same free fall. Two separated balls, however, need not retain their separation: they sample different parts of the gravitational field. For a point source, linearizing across a small separation gives the tidal tensor predictionA radial separation stretches with coefficient , whereas a transverse separation is compressed with coefficient . Initially parallel velocities therefore develop relative motion even though the individual bodies experience zero proper acceleration.
The relativistic statement is geodesic deviation. With the Riemann curvature tensor conventiona connecting vector between neighboring freely falling worldlines satisfiesHere is the covariant derivative along the reference geodesic, and its four-velocity. Curvature can be nonzero where the Christoffel symbols have been made zero. In the weak, static, slow-motion limit this equation reduces to , recovering the tidal tensor above. A finite falling lift can detect gravity through these relative accelerations; local equivalence does not imply a globally uniform field.
Weak-field connection and potential. Take and the metric signature. There is an index error in the printed formula for the Christoffel symbols: its first differentiated metric component must be , not . The correctly contracted expression isThe offending term vanishes under the stipulated time independence, so this correction does not change the intended calculation. Write and treat both and its derivatives as first order. To that order , , and . A stationary metric tensor givesFor the temporal component the inverse-metric coefficient is already first order, soFor a spatial component the zeroth-order inverse metric contributes:The time component of the approximate geodesic equation says that is constant to the retained order. In its spatial component, convert the proper time derivatives to coordinate-time derivatives and cancel :Comparison with the Newtonian equation identifies . For an isolated source, choose the gravitational potential to tend to zero at infinity and normalize the time coordinate there, giving . ThusThe quantity is the Newtonian gravitational potential, or gravitational potential energy per unit mass, in . For a point source, . A static clock has , connecting the Newtonian limit with gravitational time dilation.
Frequency of the orbiting source. Treat the gas blob as a test particle on a timelike circular Schwarzschild geodesic, with pressure and other nongravitational forces negligible. Treat our very distant location as infinity, so the observer's own gravitational potential is negligible. These are the assumptions that make a unique answer in terms of possible.
Put and use a local static observer at the emission point as an intermediate measuring frame. The remote observer lies on the symmetry axis of the orbit. A ray arriving on that axis has zero conserved axial angular momentum, so its local direction is perpendicular to the emitter's azimuthal velocity. Bending within a meridional plane does not alter this orthogonality. The transverse relativistic Doppler effect therefore giveswhere is the orbital speed measured by that local static observer. The gravitational redshift between static Schwarzschild observers then givesA gravitational circular orbit has in the weak-field limit, so . Expanding both factors,Solving for the emitted frequency givesThe gravitational part is and the transverse kinematic time dilation contributes another ; the absence of line-of-sight motion does not remove this second effect.
As an exact check, the local speed on a timelike circular Schwarzschild geodesic satisfies , where . Therefore the face-on frequency shift of a circular Schwarzschild source iswhose expansion agrees with the boxed answer. If the gas is supported or accelerated by pressure or magnetic stresses rather than following a geodesic, its orbital speed is not fixed by the mass and radius alone; the appropriate first-order result is instead , with supplied independently.
Past exam of the relativity course of the University of Cambridge 2019 Section A 3 Solution 2026-10-18
Use the geodesic Lagrangian , where dots denote an affine parameter derivative. The Euler-Lagrange equations giveThese are the geodesic equations wherever , so the Riemannian metric is nondegenerate. Substitution of , and makes both equations proportional toThus is a family of affinely parametrized geodesics, on intervals staying within one quadrant. In particular, and keep the metric nonsingular; the coordinate axes themselves are not regular points of this metric. The coordinate need not be linear in the affine parameter, despite the straight coordinate-space shape of these curves.
Past exam of the relativity course of the University of Cambridge 2019 Section B B5 Solution 2026-10-18
Write , with . On the equatorial plane, the geodesic Lagrangian isThe coordinates and are cyclic, giving . The conserved physical energy per unit rest mass is , while is the signed angular momentum per unit rest mass. The radial Euler-Lagrange equation, with , isThese are the requested geodesic equations. The equatorial condition is consistent with the polar equation by the spherical symmetry of the Schwarzschild metric.
The normalization of the four-velocity is . Insert the two conserved quantities and multiply by to obtainThis is a one-dimensional radial energy equation. Half of its left side is radial kinetic energy per unit mass plus an effective potential: the Newtonian centrifugal and gravitational terms acquire the extra attractive contribution .
A timelike circular Schwarzschild geodesic requires . Equivalently, set the derivative of to zero. At this gives , and substitution in the radial energy equation yieldsSuch timelike circular orbits require . Their coordinate angular velocity satisfies , and their proper clock rate is .
For the static North-Pole clock, . Consecutive overhead passages occur one coordinate orbital period apart, and the repeated Earth-satellite geometry gives equal signal travel delays. The comparison of circular-orbit and static Schwarzschild clocks therefore givesThis includes both gravitational and orbital-motion effects; a separate Newtonian time-dilation correction must not be added again.
For an estimate, Kepler's third law gives . The same approximate geostationary radius and period give . Expanding the ratio to first order,The satellite clock consequently gains about over a three-hour orbit in this approximation. The surface observer is taken to be static, and the spacetime model is the spherical Schwarzschild metric specified in the problem.
Past exam of the relativity course of the University of Cambridge 2019 Section B B6 Solution 2026-10-18
A fundamental observer follows the mean cosmic matter flow and is at rest with respect to the homogeneous cosmological frame. Cosmological isotropy permits no preferred spatial acceleration, rotation vector or anisotropic expansion for this flow: the congruence is geodesic, irrotational and shear-free, with isotropic expansion. Its orthogonal homogeneous spatial slices define simultaneity. Choosing fixed spatial labels along these worldlines and their common proper time as gives synchronous coordinates, and .
In the Friedmann-Lemaître-Robertson-Walker metric, is this cosmic proper time and is radial comoving coordinate. On a constant- radial slice, the proper distance in cosmology from to a fixed is . ThereforeThis is the Hubble parameter. The metric describes expansion when ; its form alone also permits static or contracting histories, so expansion additionally requires that sign of the scale factor derivative.
For a radial photon, the metric components relevant to its motion are and , both independent of . The angular momentum components vanish. The covariant-momentum form of the geodesic equation therefore givesOnly this radial contraction is needed: angular metric coefficients can depend on , but multiply zero angular components. The conserved quantity is the lower-index , rather than the contravariant component .
For outward travel put . The null condition givesHere the time coordinate is , rather than . A comoving observer has and measures photon energy . Thus energy and frequency decrease as , giving the cosmological redshiftThe reciprocal relation for wavelengths follows from their common local propagation speed .
Finally center the spatial coordinates on the receiving comoving observer. At the source, the transverse spatial line element is . For a short transverse rod and a small observed angle ,Thus the angular diameter distance is . Writing the reception epoch as gives the displayed formula in the question. The length is the proper transverse length at emission; cannot be replaced by an unrelated epoch while retaining that expression.




