The original chart has vertically and horizontally. Thus its region (a) is proton-rich relative to the beta-stable band, whereas (b) is neutron-rich.
Electron capture, , is the other proton-to-neutron weak process; it remains possible for some neutral atoms whose beta-plus decay lacks the atomic-mass threshold.The emitted alpha particle contains two protons and two neutrons. Very heavy nuclei can also compete through nuclear fission; the chart alone does not determine each nuclide's branching fractions.
- In the heavy region (e), alpha decay moves the parent down and left:
The quark transitions are followed by in (a), and followed by in (b). The additional panel shows electron capture as through W boson exchange. The remaining quarks in each nucleon are spectators.
Regions (c) and (d) lie beyond the proton and neutron binding limits, respectively. In (c), unbound protons can be emitted, ; in (d), unbound neutrons can be emitted, . These are the proton drip line and neutron drip line limits, with one- or several-nucleon emission possible according to the nuclear separation energies. They are not merely more distant points on a beta-decay trajectory.
Past exam of the particle and nuclear physics course of the University of Cambridge 2021 Section B 6 a Solution Created 2026-10-18 Updated 2026-10-20
There are three free-particle rest-energy terms and five nuclear corrections. In the paper's natural units, their meanings are:
- : the rest energy of free protons.
- : the rest energy of the atomic electrons; including this term makes the result an atomic, rather than bare nuclear, mass. Small atomic binding energies are neglected.
- : the rest energy of the free neutrons.
- , with : the attractive volume term. The short-range nuclear force mainly binds each nucleon to nearby neighbours, so the leading attraction is extensive.
- : the surface correction. Surface nucleons have fewer neighbours and are less bound; surface area grows as at approximately constant nuclear density.
- : the nuclear Coulomb energy cost of repelling protons, scaling as with nuclear radius .
- : the nuclear symmetry energy, penalizing unequal neutron and proton populations. The Pauli exclusion principle forces an excess species into higher single-particle states; strong-interaction effects also contribute.
- : nuclear pairing. It lowers the mass for even-even nuclei, raises it for odd-odd nuclei, and vanishes for odd in the stated model.
The sign convention is significant: the quantity labeled in the supplied mass formula is added to the free-particle masses and is normally negative for a bound nucleus. It is the negative of the conventional positive nuclear binding energy :The coefficients must therefore retain their printed signs; using positive while still adding it to the masses would be inconsistent.
Past exam of the particle and nuclear physics course of the University of Cambridge 2022 Section A 1 Solution Created 2026-10-18 Updated 2026-10-20
All three processes are weak charged current transformations between neighboring nuclear isobars. Neglecting neutrino masses, and writing for a neutral atomic mass, their Q values are:
- Beta-minus decay: a neutron converts to a proton, emitting an electron and an electron antineutrino,
- Beta-plus decay: a proton converts to a neutron, emitting a Positron and an electron neutrino,
These formulae use the paper's natural units. With energies in MeV, beta-plus decay requires an atomic mass-energy difference exceeding . The extra electron-mass subtraction arises from using neutral atomic rather than bare nuclear masses. Electron capture can occur when the atomic mass-energy difference is positive but below this threshold. For a particular capture shell or excited daughter, the available energy must also cover the electron-hole and nuclear excitation energies, and the small nuclear recoil. Small atomic binding corrections are suppressed in the displayed threshold formulae.
The question's fixed- family consists of nuclear isobars, rather than isotopes: isotopes have fixed . The semi-empirical mass formula gives a convex nuclear mass parabola as a function of at fixed . For odd , nuclear pairing does not split the family into two branches, so there is typically one beta-stable isobar, at the discrete minimum. Neighboring members can lower their mass by changing toward it.
For even , nuclear pairing lowers even-even nuclei and raises odd-odd nuclei, producing two offset nuclear mass parabolas. There are often two beta-stable even-even isobars, separated by an odd-odd member to which neither can energetically decay. The number is not an exact universal rule: some even- chains have one or more than two such minima against single beta decay, and a few light odd-odd nuclei are stable. Stability against single beta decay also does not guarantee stability against double beta decay.
Radiocarbon dating measures how long carbon-bearing material has been isolated from a carbon reservoir. Atmospheric cosmic rays produce secondary neutrons, which create carbon-14 chiefly throughThe carbon-14 enters atmospheric carbon dioxide and then living organisms through carbon exchange, including photosynthesis and food consumption. While exchange continues, the organism's ratio tracks the relevant environmental ratio approximately.
After exchange ceases, the remaining carbon-14 undergoes beta-minus decay,while stable carbon-12 remains. With half-life , the radioactive decay law givesThus measuring the isotope ratio , or the radioactive activity per fixed amount of carbon, givesHere is compared at equal carbon content; describe the appropriate initial reservoir. Accelerator mass spectrometry counts the rare carbon-14 relative to stable carbon directly; a decay-counting method instead measures its radioactive activity.
The initial ratio is not perfectly constant. Atmospheric production changes and reservoir differences therefore require radiocarbon calibration, often using independently dated tree rings. Contamination and subsequent carbon exchange must also be controlled. The date measures closure of the carbon system, not automatically the date of every later event involving the object. The physical half-life is about years; conventional radiocarbon ages historically use years and must be calibrated before interpretation as calendar dates.[ref]
Radiocarbon calibration by Oxford Radiocarbon Accelerator Unit. Physical versus conventional half-lives and calibration against tree rings
Neon has and sodium has , while is unchanged. The conversion is therefore beta-minus decay,A neutron is converted to a proton by the weak charged current. If an excited daughter is populated, subsequent gamma decay produces the observed photons without changing either or . The initial weak transition and the later electromagnetic nuclear de-excitation are distinct stages. A direct transition to the daughter ground state produces no nuclear de-excitation gamma ray.
Past exam of the particle and nuclear physics course of the University of Cambridge 2022 Section B 6 e Solution Created 2026-10-18 Updated 2026-10-20
The table gives the Xi baryon mean lifetime . At , an initially resting particle has survival probabilityThus the most probable contents are one undecayed . The initial momentum is unspecified. For a moving parent, time dilation replaces the denominator by , making the survival probability at least as large. The times below are characteristic proper mean lifetimes; laboratory times depend on the particle velocities.
The principal first step isIt typically occurs on the scale. The neutral pion almost immediately converts to two photons, with and . The Lambda baryon has and two dominant routes.
In the charged-pion route,The muon lifetime is a standard additional input, not present in the supplied five table pages.[ref]
Review of Particle Physics by Particle Data Group (2022). Muon listing, mean-life entry: approximately 2.197 microseconds
The successive contents are approximately , then , then . After a few muon lifetimes the dominant stable endpoint isThe leading-path probability including the tabulated two-photon pion branch isHere the last factor is the tabulated dominant muonic charged-pion fraction; rare radiative corrections are being neglected in describing a fixed photon count. Before selecting pion decay channels, the probability of reaching the history is .In the neutral-pion route,This produces by roughly the nanosecond scale. It is a long-lived intermediate state, not the final endpoint: the free neutron has in the original table and eventually undergoes beta-minus decay,Thus after several thousand seconds the dominant stable endpoint isBefore selecting the two decays, the history has probability . The familiar rough description is therefore a charged-pion route and a neutron route; including the specified leading pion branches gives approximately and for the two displayed endpoints. The remainder includes Dalitz decays and other rare channels, not a failure of probability conservation.
These are particle decay cascades, treating the separated final proton, electron, photons and neutrinos as stable asymptotic particles and neglecting subsequent collisions and rare extra radiation. An infinitely large box prevents escaping particles from being removed from the inventory. Neutrino labels specify their production flavours. Each lifetime describes a stochastic waiting time, so there is no finite sharp instant at which every unstable particle has certainly decayed.
Past exam of the particle Astrophysics course of the University of Cambridge 2015 Paper 1 2 Solution Created 2026-10-20 Updated 2026-10-20
Particle candidate. A stable, electrically neutral weakly interacting massive particle can become nonrelativistic before cosmological particle freeze-out. Its annihilation rate per particle eventually falls below the Hubble parameter; the surviving comoving number then remains approximately fixed. A weak-scale annihilation cross section can give a cosmologically significant thermal relic. This is a mechanism and a parameter-scale motivation, not a guarantee that every weakly interacting particle has the right abundance.
supersymmetry supplies neutralinos, mixtures of neutral electroweak gauginos and higgsinos. If a neutralino is the lightest supersymmetric particle and R-parity is conserved, it cannot decay solely into Standard Model particles and is stable. Its electroweak interactions can make it a WIMP. Conservation of R-parity and a neutral lightest state are additional assumptions; R-parity violation, coannihilation, composition and resonant annihilation can substantially change the conclusion.
An underground test. XENON100 at Gran Sasso used a liquid-xenon target in a two-phase time projection chamber. A WIMP scattering elastically from a xenon nucleus could produce a low-energy nuclear recoil. The interaction makes prompt particle scintillation, S1, and ionization electrons. An electric field drifts the electrons upward; their extraction into xenon gas produces delayed electroluminescence, S2. The delay measures depth, while the S2 light pattern determines the transverse position. An inner fiducial volume suppresses surface backgrounds through xenon self-shielding; underground overburden reduces cosmic-ray muons, and shielding and material selection reduce radioactivity.[ref]
The XENON100 Dark Matter Experiment by the XENON100 Collaboration. Detector design, signal formation and background-rejection principles
The S2/S1 ratio separates most electron recoils from nuclear recoils. Gamma-source calibration maps the electron-recoil leakage; an americium–beryllium neutron source calibrates nuclear-recoil response and cut acceptance. Purity and position corrections must be measured, and selection fixed before unblinding the search region. neutrons can themselves produce single nuclear recoils, so discrimination is not perfect; material assays and transport simulations constrain this background. In the 224.6-live-day, 34-kg analysis, two candidate events were compatible with the expected background events. The result constrained scattering cross sections rather than establishing a discovery.[ref]
Dark Matter Results from 225 Live Days of XENON100 Data by the XENON100 Collaboration. Pages 2–4, calibration, blinded selection, neutron background and candidate counts
A predicted count also depends on the local dark matter halo density, distribution of velocities, recoil threshold and nuclear response. Thus a null result constrains a particle model under stated astrophysical assumptions; it does not exclude all dark matter. A collider missing-momentum signal would likewise need independent evidence for a cosmological lifetime.
Original functional schematic of prompt light and delayed charge readout in a two-phase xenon detector
. Details. Relic energy density in the stipulated freeze-out approximation. Let and . Writing the given distribution in energy units givesBy sharp-freeze-out relic dilution, after cosmological particle freeze-out conserve particle number, . In the approximation for the background bath,Inserting the printed inputs yieldsand henceThis is approximately of the stipulated dark-matter energy density, , so the toy calculation gives the right order and is close to the target. At fixed the cancellation of in is exact for the given prefactor, while the present energy density remains proportional to .
The equilibrium exponential must be evaluated at freeze-out, not at today's temperature: equilibrium no longer maintains the particle number afterward. More accurately, comoving entropy conservation gives and multiplies the displayed by , when both counts use the same bath-temperature convention. Thus is the constant- estimate supported by the supplied toy model. A refined abundance would require additional entropy degrees of freedom and annihilation history: realistic entropy release, gradual freeze-out and the model's annihilation channels matter.
Original calculation of the relic-density sensitivity to freeze-out parameter, with the printed mass and constant-entropy-degrees approximation
. Details. The tau-neutrino charged-current threshold requires specifying the stationary target and the lightest allowed final state. For a free neutron, the lowest charged current channel is . At threshold both final particles are at rest relative to one another in the centre-of-momentum frame, soThe equal-nucleon-mass approximation gives . More generally for a target of mass and a recoil system with minimum allowed invariant mass . A stationary electron in instead gives . The customary answer therefore presumes a nucleon target; nuclear thresholds and practical deep inelastic scattering thresholds differ.
Use the leading-order parton model: scatter incoherently from an approximately on-shell collinear quark carrying nucleon momentum fraction , neglect quark and lepton masses, use an unpolarized target, and neglect nuclear binding and higher-twist corrections. The condition suppresses target-mass effects, while permits the local Fermi interaction instead of the full W propagator. CKM-weighted accessible final flavours are approximated by their leading light-quark sums. The struck-quark centre-of-mass energy is , with .
A neutrino scatters through or , and through the corresponding crossed antiquark channels such as . The chiral charged current makes the massless quark contribution independent of and the antiquark contribution proportional to . The scattering probability is weighted by the parton distribution functions; the explicit factor comes from . In the usual convention is a number probability density, while is a momentum density. Approximate Bjorken scaling leaves mainly dependence; QCD evolution adds a logarithmic dependence.
The printed proton-density formula is not an isoscalar formula in the standard PDF convention. For a proton, neglecting incoming charm and taking accessible CKM sums as unity, the conventional leading-order result isFor an isoscalar target per nucleon, average proton and neutron and use charge symmetry of nucleon parton distributions: , , . This givesThe standard normalization follows equivalently by inserting and into the charged-current structure-function formula.[ref]
structure functions by Particle Data Group (2024). Section 18.1, Eqs. (18.8) and (18.19): charged-current normalization and proton quark combinations
A concrete discrepancy remains even with a simple valence model: take , and all sea densities zero. The correctly averaged isoscalar bracket is , while the printed bracket is only with the same prefactor. Thus the intended helicity and dependence can be explained, but the literal printed isoscalar claim cannot be derived. If the symbols were instead defined as momentum densities, the extra explicit would also need removal.
Assume approximate charge symmetry of nucleon parton distributions, the interchange of up quarks and down quarks under the isospin rotation carrying the proton into the neutron:Corrections from the up quark-down quark mass difference and the electromagnetic interaction are neglected. With the proton-only shorthand in d,If charm is active, add the same to each; heavier flavors are treated similarly. These formulae use the same and factorization convention for all parton distribution functions.
Subtracting the deep-inelastic structure functions in e givesThus at moderate and large , the charge-weighted up quark content of the proton exceeds its down quark content. In the valence quark dominated regime this is consistent with the valence structure, compared with for the neutron. The larger up quark electric charge makes the proton scatter more strongly. This observation alone does not establish pointwise: the valence-number sum rules constrain integrals, not every bin.
If the small- observation means equality to good relative accuracy, it supports dominance by approximately charge-symmetric sea quarks, with and negligible relative valence excess. Gluon splitting creates quark-antiquark pairs, and the leading strong interaction treats light quark flavors similarly. It does not follow that every sea quark flavor has exactly the same distribution at every .
Logical qualification. Equality of the limiting values alone is weaker than equality of their ratio. For example , , near gives and : both tend to zero, although and . The usual inference about a symmetric sea needs or equivalent information about relative differences, rather than merely coincident zero limits.
Past exam of the particle physics course of the University of Oxford 2022 6 d iii Solution 2026-10-25
A fission reactor supplies predominantly electron antineutrinos, with typical energies of a few MeV. Even if they oscillate to muon antineutrinos, producing a real muon through a charged current requires roughly the muon rest energy, over MeV for a free nucleon target. For example,Thus a muon spectrometer cannot observe this appearance channel from a reactor. Measure electron antineutrino disappearance instead, most commonly through inverse beta decay, , using the prompt Positron and delayed neutron signal.
A Positron signal is correct for the reactor's antineutrinos, through inverse beta decay,A true electron neutrino charged current interaction instead produces an electron, for example . This corrects the source's loose use of “neutrino” for the reactor beam.
After slowing, the Positron annihilates with an electron, generally producing two keV photons. The prompt visible energy includes both the Positron kinetic energy and annihilation energy; neglecting the small neutron recoil,A delayed neutron capture supplies a powerful coincidence tag. Detecting only two annihilation photons discards useful prompt energy and does not uniquely identify the charged current event.
Change is compatible with natural kinds, provided there is a defensible basis for tracking membership and explaining the changing properties. Requiring every property to remain unchanged would exclude nearly all physical objects. The important distinction is between variation within a kind, a transition out of it, and changes in the population that constitutes it.
Chemical elements offer a relatively sharp case. A carbon atomic nucleus has atomic number six, meaning six protons. Its isotope depends also on its neutron number; the ionization state of a carbon chemical atom can change without changing its chemical element. Temperature, position and velocity can also change. Classifying these objects together is useful because the relevant common constitution supports further inference, not because their entire property lists are identical at every moment.
A nuclear reaction that changes the proton number is different: it can produce a nucleus of another chemical element. This does not refute the original classification. It identifies a process under which membership changes. A theory of natural kinds should permit transformations between kinds rather than require its members to exist forever. The ordinary criterion also has a domain: an arbitrary mixture containing carbon is not itself a single carbon chemical atom.
Water makes a complementary point. A sample can undergo melting or boiling, changing density, rigidity and transport properties while retaining its ordinary chemical identification. The claim must be qualified: a bulk sample contains interacting molecules, and its detailed composition can include dissociation products. It need not consist at every instant exclusively of isolated identical water molecules. Nevertheless, changes of thermodynamic phase are explained through the constitution and organization of the material, rather than by treating every different appearance as a new unrelated substance.
These examples might suggest that some fixed microscopic essence is always required. Species put pressure on that inference. Individuals develop and differ; the distribution of inherited traits can change across generations through natural selection, genetic drift and gene flow. A demand that every member share an unchanging diagnostic appearance would misrepresent this history. It would also make a change in the frequency of one trait automatically create a new species, which is not how the relevant evolutionary processes work.
Homeostatic property cluster theory provides one alternative. Traits can tend to occur together because common development, shared ancestry and interactions within a population sustain their association. The traits need not be universal, and the maintaining processes need not freeze their frequencies. A population can change while retaining enough historical and causal continuity to support useful inference.[ref]
Homeostasis, Species, and Higher Taxa by Richard Boyd. sections 0.0–0.1, the relation between explanatory classification and causally maintained property clusters
This is not a claim that every species concept gives the same boundaries. Reproductive relations, descent and ecological processes can motivate different criteria for different investigations.An objection remains: if both members and their traits change, what prevents a natural kind from becoming a mere convenient label? The answer cannot be resemblance alone or an arbitrary chain of small changes. The proposed grouping must track processes that support reliable explanations and suitably qualified predictions. If the processes maintaining a cluster break down, or a lineage divides into independently evolving populations, continuing to use one label may cease to serve the relevant inquiry. Membership can be uncertain near such transitions without making every central case arbitrary.
There is also no requirement that all natural kinds have the same basis of unity. The atomic number criterion and a historically sustained population answer different scientific questions. Imposing the former structure on every biological grouping would mistake one successful form of classification for a universal metaphysical rule.
Changing properties therefore do not by themselves defeat naturalness. The scientific work lies in identifying which variations a kind tolerates, which transformations end membership, and why its remaining unity supports inference. A classification earns its status through that explanatory achievement, not through the fiction that nature is motionless.
The initial total momentum is zero, so the outgoing neutron recoils with momentum magnitude . Put . Conservation of relativistic energy givesFor example the rest energies , and for the proton, charged pion and neutron give this value.[ref]
Review of Particle Physics by Particle Data Group (2022). Charged-pion, proton and neutron listings, page 1 of each: mass values in MeV
The result is smaller than the initial-to-final rest-energy difference of about , because some released energy becomes neutron recoil kinetic energy. Atomic binding of a captured pion is neglected in the stated stationary-particle model.For annihilation of a phonon ,For phonon creation,The signs follow whether the neutron gains or loses the phonon's energy and crystal momentum. These are one-phonon coherent inelastic neutron scattering conditions, with accounting for lattice periodicity.
Past exam of the physics A course of the University of Cambridge 2011 Paper 1 Section C C10 Solution 2026-10-20
For this calculation define the net wavevector gained by the neutron as , the opposite of a common sample-transfer convention. Since ,The perpendicular neutron recoil and phonon absorption condition therefore requires . In the supplied periodic dispersion, interpret its as this transfer in the extended-zone representation of a phonon dispersion. Put and . Nonzero intersections obeyThere is no root in : there and . On the ratio increases strictly from to infinity, so exactly one root occurs. Nor can there be a higher root: gives , with strict inequality at the possible boundary. For , use ; throughout this short interval, since its minimum there is . Thus the only nonzero magnitude satisfiesSolving the exact dispersion, which is permitted instead of the linear approximation, givesA straight chord between the zone edge and the next zone centre gives . Its intersection solves , yielding and as a less accurate estimate.
The reduced-zone phonon wavevector is along the chosen positive transfer direction. The difference is a reciprocal-lattice vector, not an additional independent phonon outside the first zone. At low temperature the absorption probability contains the Bose-Einstein distribution factor , which tends to zero. Here , so this absorption channel is strongly suppressed well below that scale. elastic scattering and kinematically allowed spontaneous phonon creation need not disappear.
Past exam of the physics A course of the University of Cambridge 2012 Paper 1 Section B B8 Solution 2026-10-20
matrix multiplication gives , hence . For physical neutron spin, use , so , , and measurement along any axis gives .
For the specified field, . The Time-dependent Schrödinger equation is with . The uniform-field spin precession follows from :
The measurement direction is , as confirmed by the original diagram. Write and . The spinors and have unit norm and inner product . Applying gives eigenvalues and . At they are the usual basis; at they are the basis up to a phase; at the up/down roles are exchanged, with a factor ; and at both return with a minus sign. A spinor changes sign under a full rotation, while its isolated-state measurement probabilities are unchanged.
For spin measurement in the yz plane, projection givesFor these are ; for both are at all times; for they are exchanged; and for they are the same as at zero angle. The constant probabilities also follow from conservation of .
Past exam of the physics A course of the University of Cambridge 2021 Paper 1 Section A 3 Solution 2026-10-18
A Stern-Gerlach experiment sends a collimated beam through an inhomogeneous magnetic field and then measures its transverse position after a drift region. The neutron is electrically neutral but has a nonzero magnetic moment proportional to its spin, . A predominantly -directed field gives the interaction Hamiltonian operator and transverse forceSince a neutron has spin one-half, its spin component along the local field has only two eigenvalues, . Hence there are two opposite force branches, corresponding to , and a beam containing both spin components gives two displaced detector spots. This is neutron Stern-Gerlach splitting, not an electric-charge Lorentz force. A uniform magnetic field can cause Larmor precession but does not provide the required separating magnetic field gradient.
The neutron's gyromagnetic ratio is negative, so its magnetic moment points opposite to its spin; this reverses which spin label goes to which spot without changing the two-way splitting. Equal populations occur for an initially unpolarized beam. A beam prepared entirely in one field-axis spin eigenstate gives only its corresponding branch, explaining the qualification “in general”.




