Past exam of the mathematics course of the University of Cambridge 2025 iii Paper 105 3 a Solution Created 2026-09-24 Updated 2026-09-25
For and , define the characteristic curve byThe bounded derivative makes globally Lipschitz, uniformly in . On each finite time interval, , so Gronwall inequality prevents finite-time escape. The Picard-Lindelof theorem therefore gives a unique trajectory for every finite . Differentiation in givesso the characteristic flow map is a increasing diffeomorphism.
Along a characteristic, the chain rule changes the equation intoTracing backward by the flow therefore givesThe regularity of the flow makes this a classical solution. Conversely, every classical solution obeys the same ordinary differential equation along every characteristic, so the formula also proves uniqueness.
Past exam of the mathematics course of the University of Cambridge 2025 iii Paper 359 1 b i Solution Created 2026-09-24 Updated 2026-09-25
On the finite-dimensional space , the Galerkin equation is an autonomous system of ordinary differential equations whose right-hand side is a quadratic polynomial in the coefficients of . It is locally Lipschitz, so the Picard-Lindelof theorem gives a unique maximal local solution.
Taking the inner product with givesThe advecting field is divergence free. Periodicity and the skew-symmetry of incompressible transport therefore make the nonlinear term zero. HenceA finite-dimensional solution can cease to exist only if its norm diverges. This uniform bound prevents such blow-up, so the solution extends uniquely through every interval .
Past exam of the mathematics course of the University of Cambridge 2026 iii Paper 359 1 b ii Solution Created 2026-09-24 Updated 2026-09-25
The first equation determines linearly from :Substitution into the second equation gives an ordinary differential equation on the finite-dimensional space . Its right-hand side is polynomial, and therefore locally Lipschitz continuous. The Picard-Lindelof theorem supplies a unique local solution. The energy estimate in part (iii) bounds on every finite time interval, so the finite-dimensional continuation criterion rules out finite-time escape. The solution is consequently unique on every interval .