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ADP contains the same adenosine unit as ATP, with two phosphate groups instead of three. One ATP converted by the stated hydrolysis gives one ADP and one inorganic phosphate: $3=2+1$ accounts for the phosphate groups while adenine and ribose are retained. ADP is therefore a reusable material carrier, rather than ATP with its entire structure discarded.

Regeneration reverses the net chemical reaction:At the same stipulated reference conditions its $\Delta G^{\circ \prime }$ is $+30.5\mathrm{kJ}\mathrm{mo}{\mathrm{l}}^{-1}$, the negative of the hydrolysis value. It is an endergonic reaction and requires energy input through energy coupling; a catalyst alone cannot supply that input. Recycling the material carrier does not recycle the expended driving energy. Cellular respiration and light-dependent reactions supply routes for regeneration. See Cooper, The Cell: ATP generation and energy coupling.

ADP is a nucleotide with two phosphate groups. Formation of ATP from ADP and phosphate couples to energy supply in light-dependent reactions; the Calvin cycle returns ADP after using ATP. ^[ref].

ATP is a nucleotide consisting of adenosine, itself adenine joined to ribose, carrying three phosphate groups. From the ribose outward, these groups are labelled $\alpha$, $\beta$, and $\gamma$. ATP connects energy-supplying processes to energy coupling for synthesis and active transport; the same carrier can be regenerated and reused. ^[ref].

The net hydrolysis commonly used in energy coupling isHere ${\mathrm{P}}_i$ denotes inorganic phosphate. At buffered pH $7$, this biochemical shorthand groups the appropriate protonation states into pools and leaves proton exchange with the buffer solution implicit. An explicit, charge-balanced choice is ${\mathrm{ATP}}^{4-}+{\mathrm{H}}_2\mathrm{O}⟶{\mathrm{ADP}}^{3-}+{\mathrm{HP}{\mathrm{O}}_4}^{2-}+{\mathrm{H}}^{+}$, without implying these are the only chemical species present. See the IUBMB recommendations for biochemical thermodynamics.

The quoted textbook biochemical standard state value is approximatelyThis convention uses fixed pH $7$, temperature $298.15\mathrm{K}$ ($25{}^{\circ }\mathrm{C}$), reference pressure $100\mathrm{kPa}$ ($1\mathrm{bar}$), unit reference thermodynamic activities for dissolved reactants and reaction products, and water thermodynamic activity approximated by one. The prime indicates the fixed-pH biochemical convention. See OpenStax Biology 2e, 6.4: standard ATP hydrolysis value and Biology 2e, 6.2: biochemical standard conditions. This is a reference value, rather than a universal value inside a biological cell; precise tables must also specify chemical solution conditions and any magnesium ion binding convention. Different reference conventions and data treatments give different tabulated values, as discussed in Li et al., 2010: a database of thermodynamic quantities for biochemical reactions.

An exergonic reaction has a negative change in Gibbs free energy, so the overall ATP hydrolysis is favourable under those reference conditions. Breaking a chemical bond by itself costs energy; forming new chemical bonds can release energy. The net change compares all reactants with all reaction products, including their interactions with water and the entropy contribution. Calling the phosphate connection a "high-energy bond" describes a large favourable change in Gibbs free energy on hydrolysis, rather than energy released by bond breaking alone. See 7.5 Strengths of Ionic and Covalent Bonds and Cooper, The Cell: ATP and metabolic energy.

Composition changes the driving force. At the same fixed pH, temperature, pressure, and binding convention, write the molar reaction change asHere $R$ is the molar gas constant, $T$ the absolute temperature, and $a$ a dimensionless thermodynamic activity for a biochemical pool. Constant water thermodynamic activity is absorbed into the reference term; fixed pH accounts for buffered protons. The shorthand $\Delta G$ means transformed molar reaction Gibbs free energy change, ${\Delta }_r{G}^{\prime }$, rather than a finite sample's total change. The natural logarithm acts on a dimensionless reaction quotient, never on concentrations with units. See the IUBMB biochemical thermodynamics recommendations and the general equilibrium constant relation.

For a stipulated ideal dilute chemical solution, let $a_i=[i]/c^{\circ }$, with $c^{\circ }=1\mathrm{mol}{\mathrm{L}}^{-1}$. Choose $[\mathrm{ATP}]=5\mathrm{mmol}{\mathrm{L}}^{-1}$, $[\mathrm{ADP}]=0.5\mathrm{mmol}{\mathrm{L}}^{-1}$, and $[{\mathrm{P}}_i]=1\mathrm{mmol}{\mathrm{L}}^{-1}$, ignoring activity coefficient corrections and magnesium binding. These are illustrative inputs, not a claim about a particular biological cell. ThenandIncreasing $Q$ tenfold raises $\Delta G$ by $RT\ln 10\approx 5.708\mathrm{kJ}\mathrm{mo}{\mathrm{l}}^{-1}$ at this temperature. Thus the ATP to ADP ratio and available inorganic phosphate matter, even with the same standard state value. These are local molar predictions at the stipulated composition, rather than a constant total yield as an isolated sample reacts.

Hexokinase provides a concrete connection between sugar chemistry and energy coupling: it transfers a terminal phosphate group from ATP to glucose, forming a phosphorylated sugar and adenosine diphosphate. The enzyme accelerates the transfer, while consuming ATP changes the net chemical reaction being carried out. The donated group reaches the substrate through the catalytic route.^[ref]

For a symbolic teaching model, write $S$ for an unphosphorylated sugar, $S\text{-}P$ for its phosphorylated form, and $P_i$ for inorganic phosphate. These are labels for chemical states, not complete elemental formulas. Using one consistent reference convention at fixed pH and temperature, stipulate the following molar changes in Gibbs free energy:All three numbers are chosen illustrative values, not measured properties of glucose or a particular enzyme. The prime marks a biochemical reference convention with pH held fixed; explicit proton and metal-binding bookkeeping is suppressed consistently. The first two lines are a thermodynamic decomposition: cancelling water and inorganic phosphate gives the net transfer. They do not assert that the reaction mechanism first releases free inorganic phosphate and then recaptures it.

Because Gibbs free energy is a state function, consistently defined reaction changes add. A working reaction mechanism must also connect the desired conversion to ATP consumption; independently allowing ATP hydrolysis beside the sugar does not establish energy coupling. The general distinction is developed under energy coupling. ATP-dependent phosphorylation of a membrane protein can likewise connect a chemical change to active transport.^[ref]

Actual Gibbs free energy changes depend on thermodynamic activities. Even a favourable reference sum can be overcome by accumulation of reaction products or depletion of ATP; it supplies no prediction of the reaction rate. A living biological cell also regenerates ATP. Sustained operation therefore requires a connected metabolism, not an inexhaustible stock of a special molecule.

ATP synthase is a molecular motor that couples downhill proton movement across a cell membrane to formation of ATP from ADP and inorganic phosphate. In oxidative phosphorylation, this is the machinery that makes chemiosmosis productive: an electrochemical gradient becomes reusable chemical driving capacity.^[ref]

Its usefulness is a conversion between currencies. A membrane-spanning proton-motive force can power a local machine, while newly formed ATP can participate in energy coupling elsewhere. The enzyme supplies a route between these forms of free energy; it cannot make an energetically uphill total cycle favourable merely by accelerating its chemistry.

Define side $P$ as the higher proton electrochemical potential reservoir and side $N$ as the synthesis-side reservoir. For transfer $P\to N$ at common temperature $T$, define the positive downhill proton-motive force magnitude $\Delta p_{\mathrm{drive}}$ byHere $a$ is thermodynamic activity, $\psi$ is electric potential, $R$ is the molar gas constant and $F$ is the Faraday constant. Thus both a higher proton thermodynamic activity and a more positive electric potential on side $P$ contribute to the driving magnitude. This definition fixes the sign; conventions for a signed proton-motive force differ. The calculation under chemiosmosis separates these two contributions numerically.

Assume fixed reservoirs, tight mechanical energy coupling, one transported proton per $c$ subunit per revolution, and three ATP produced per revolution. Neglect leaks, slipping and membrane transport of the chemical reagents. Let $g_{\mathrm{ATP}}>0$ be the local molar Gibbs free energy cost of ATP formation at the stipulated composition, pH and magnesium-binding convention. It is not necessarily the standard state value. Adding changes in the state function gives, per mole of complete turns,For this model net synthesis is thermodynamically favoured when $\Delta G_{\mathrm{turn}}<0$. Equality is a reversible balance, not a promise of a useful reaction rate. A negative value establishes an available driving margin; it does not specify how fast the enzyme runs.

Choose $n=10$, $g_{\mathrm{ATP}}=50.0\mathrm{kJ}\mathrm{mo}{\mathrm{l}}^{-1}$, $F=96485\mathrm{C}\mathrm{mo}{\mathrm{l}}^{-1}$ and $\Delta p_{\mathrm{drive}}=0.180\mathrm{V}$. These are illustrative inputs, not measurements of the preparation in the experiment below. Thenand $\Delta G_{\mathrm{turn}}=-23.673\mathrm{kJ}\mathrm{mo}{\mathrm{l}}^{-1}$. Per ATP, the ideal input is $57.891\mathrm{kJ}\mathrm{mo}{\mathrm{l}}^{-1}$, leaving a driving margin of $7.891\mathrm{kJ}\mathrm{mo}{\mathrm{l}}^{-1}$. The balance point isAt $0.140\mathrm{V}$ the same synthesis cycle instead has $\Delta G_{\mathrm{turn}}=+14.921\mathrm{kJ}\mathrm{mo}{\mathrm{l}}^{-1}$: the chosen reservoirs favour its reverse.

The machine is reversible: sufficient ATP hydrolysis can drive opposite rotation and pump protons uphill. Actual direction also depends on inhibition and available substrates; a weak proton-motive force need not make every intact enzyme immediately run backward. Respiratory uncoupling supplies a different failure mode: a parallel proton leak dissipates the gradient without productive shaft rotation.^[ref]

The motor budget $10/3$ is not the whole cost of ATP delivered outside a mitochondrion. Import of ADP and inorganic phosphate, and export of ATP, also draw on the electrochemical gradient.^[ref] For a deliberately simplified system budget, assign these transports together one additional downhill-proton equivalent per delivered ATP, valued at the same $F\Delta p_{\mathrm{drive}}$. This is a chosen accounting convention, not a claim of one extra literal proton through $F_0$, nor a universal transport stoichiometry. The total becomes $10/3+1=13/3$ equivalents and $75.258\mathrm{kJ}\mathrm{mo}{\mathrm{l}}^{-1}$ of gradient expenditure per delivered ATP at $0.180\mathrm{V}$. The ratio of stored chemical free energy to that expenditure is $50/75.258\approx 66.4\%$, compared with $50/57.891\approx 86.4\%$ for the motor alone. This system budget changes the resource expenditure, not the motor's balance point $\Delta p_{\ast }$. Real transport terms require their own electrochemical potentials, and leaks add further cost.

The membrane motor $F_0$ contains a rotating ring of $c$ subunits beside stationary subunit $a$. Two offset water-accessible half-channels connect opposite membrane sides to the ring. A proton enters one half-channel and protonates a glutamic acid residue on a $c$ subunit; neutralization permits that site to enter the hydrophobic lipid bilayer. Rotation carries it around to the other half-channel, where it releases the proton. A conserved arginine in subunit $a$ helps separate the routes and promotes release. Downhill proton transfer biases rotation; this is not a freely open transmembrane pore.^[ref]

The central shaft transmits torque to $F_1$; a peripheral stalk prevents the catalytic head from simply co-rotating. Its three $\beta$ catalytic sites, within an ${\alpha }_3{\beta }_3$ head, cycle through different binding shapes. In the simplified binding-change picture, a loose site captures ADP and inorganic phosphate, a tight site favours bound ATP, and opening releases ATP. Rotation changes binding and release as well as chemistry.^[ref]

One complete, tightly coupled turn cycles each catalytic site once, producing three ATP molecules. If the ring has $n$ proton-binding subunits, the ideal motor budget is $n$ transferred protons per turn, or $n/3$ per ATP. Ring size varies between organisms; the worked example chooses $n=10$, as in the studied bacterial systems, rather than assigning ten to every ATP synthase.^[ref]

For this example the ring's repeat angle is $360^{\circ }/10=36^{\circ }$, whereas the three-site catalytic cycle repeats after $120^{\circ }$. Their ratio is $10/3$, not an integer. Counting complete turns avoids inventing a fixed integer proton count for every catalytic event. The schematic does not require both parts to advance simultaneously as rigid gears; elasticity allows temporary twisting while their cycles proceed.^[ref]

Follow one glucose through canonical glycolysis, with no diversion of intermediates into other metabolic pathways. The investment stage uses two ATP to prepare the six-carbon substrate. Cleavage and rearrangement provide two glyceraldehyde 3-phosphate molecules, each containing three carbon chemical atoms. Each then yields one three-carbon pyruvate, one NADH, and two ATP in the payoff stage.^[ref]

The material check is $6=2\times 3$: all six carbon chemical atoms remain in the two pyruvates. No carbon dioxide has been released within this boundary. In the ATP ledger, each three-carbon route contains two ATP-forming transfers, soThe first pair of payoff transfers only restores the initial ATP inventory; the second pair creates the net gain. Four newly formed ATP is therefore compatible with only two additional ATP remaining.

For an original scaled example, stipulate complete conversion of $5\mu \mathrm{mol}$ of glucose. The initial $30\mu \mathrm{mol}$ of carbon chemical atoms becomes $10\mu \mathrm{mol}$ of pyruvate, still containing $30\mu \mathrm{mol}$ of carbon chemical atoms. The pathway spends $10\mu \mathrm{mol}$ of ATP, forms $20\mu \mathrm{mol}$ of ATP, and adds $10\mu \mathrm{mol}$ to the ATP inventory before any other ATP use. It also reduces $10\mu \mathrm{mol}$ of NAD+. These are calculated ideal amounts, not observed yields; side routes or incomplete conversion change the outcome.

A common biochemical net chemical equation isHere ${\mathrm{P}}_i$ is inorganic phosphate. The names group biochemical protonation and metal-binding states; the displayed proton and water terms use a common shorthand rather than a unique specification of every chemical species. The robust ledger records two net ADP-to-ATP conversions and two NAD+-to-NADH conversions. Summing the individual chemical equations cancels two invested ATP against four formed ATP and cancels the internal substrates, giving those coefficients.

In the payoff stage of glycolysis, oxidation of glyceraldehyde 3-phosphate is coupled to reduction of NAD+. Each NADH carries a two-electron reducing equivalent. The formal half-chemical equationmakes the electron count explicit: two NADH per glucose carry four electrons. This is redox bookkeeping, not a claim that free electrons travel through the chemical solution or that NADH is itself ATP.

Fermentation can return NADH to NAD+ by reducing an organic substrate; reduction of pyruvate to lactate is one example. In aerobic cellular respiration, reducing equivalents reach an electron transport chain, reducing molecular oxygen. Other forms of cellular respiration use other electron acceptors, so absence of oxygen does not uniquely imply fermentation.^[ref]

The need for NAD+ regeneration follows from a finite-pool argument. In a hypothetical closed preparation with $12\mu \mathrm{mol}$ of initially oxidized NAD+ and no regeneration, at most $6\mu \mathrm{mol}$ of glucose can complete the two NAD+-consuming conversions per glucose. This is an upper bound even with excess glucose, not a predicted stopping time: other limitations can stop the preparation earlier. With an intact fixed nicotinamide adenine dinucleotide pool and no side reactions, converting NAD+ into NADH preserves their sum but depletes the usable oxidized form.

ATP recycling imposes a second condition. Glycolysis needs some initial ATP for investment and consumes two net ADP and two inorganic phosphate per completed glucose. In a closed ideal preparation with only $8\mu \mathrm{mol}$ of initial ADP, no other source of ADP, and enough initial ATP and inorganic phosphate, at most $4\mu \mathrm{mol}$ of glucose can finish. This bound follows from the net ADP consumption, even though investment temporarily produces additional ADP. Initial investment also means that adequate final inventories alone cannot guarantee the route can start.

For continued operation at fixed carrier inventories, other chemical reactions must match the two net ATP formed per glucose with ATP use that restores ADP and inorganic phosphate, or exchange must supply those reactants. ATP hydrolysis coupled to cellular work is one route. Thus glycolysis can sustain useful energy coupling while neither its ATP inventory nor its NADH inventory grows indefinitely; matter cycles while glucose supplies fresh chemical free energy.

Inorganic phosphate, abbreviated ${\mathrm{P}}_i$, denotes the free phosphate pool in biochemical chemical equations, including ATP hydrolysis. Its constituent chemical species depend on pH and protonation; ${\mathrm{P}}_i$ does not specify a single electric charge or proton count. See the IUBMB recommendations on biochemical reactant pools.

In Respiratory enzymes in oxidative phosphorylation. I. Kinetics of oxygen utilization (1955), Britton Chance and G. R. Williams examined isolated liver mitochondria in isotonic medium with substrate and inorganic phosphate. A one-millilitre optical cuvette held the suspension. A vibrating platinum electrode lay outside the light path; calibrated electric current followed dissolved oxygen, with rapid changes recorded by a galvanometer oscillograph. Air-saturated and oxygen-depleted readings checked sensitivity. Their Figure 2 shows ADP additions accelerating oxygen consumption, followed by return to slow respiration; repeated additions restored acceleration. Figure 4B compares delayed substrate addition after ADP incubation with the reverse order, supporting little unrelated ADP loss in that preparation. These comparisons support coupling to ADP utilization. The authors discuss dilution, sensitivity changes and atmospheric oxygen entry, which especially biases slow respiration. The readout did not directly measure the membrane potential or prove the later chemiosmosis mechanism.^[ref]

A control can test either the instrument or the biology. Calibrating electric current against oxygen checks the former; comparing responses before and after an ADP addition checks the latter. A valid calibration cannot by itself establish ATP formation, and a repeatable biological response cannot by itself fix an instrument's sensitivity.

NADH supplies two electrons to respiratory complex I, then ubiquinone, respiratory complex III, cytochrome c and cytochrome c oxidase; terminal oxygen reduction forms water. Succinate dehydrogenase, or respiratory complex II, supplies another entry to ubiquinone. Respiratory complex I, respiratory complex III and cytochrome c oxidase move protons outward; respiratory complex II does not.^[ref]

For an original electron balance, supply exactly $6\mu \mathrm{mol}$ of NADH to an ideal preparation with no other electron donor or competing electron acceptor. The donor supplies $12\mu \mathrm{mol}$ of electrons. Complete reduction of one oxygen molecule needs four electrons, so the corresponding oxygen consumption is $3\mu \mathrm{mol}$. Adding the two formal half-reactions makes the result explicit:The cancelling electrons determine the donor-to-oxygen ratio. These chemical equations do not count transmembrane protons or determine an ATP yield. Chemical protons consumed in water formation and transported protons have different roles in the ledger.

Oxidative phosphorylation couples respiratory redox conversion to ATP formation through chemiosmosis. ATP synthase uses inward proton flow to join ADP and inorganic phosphate.^[ref]

The intermediate electrochemical gradient explains why respiratory uncoupling can preserve oxygen consumption while reducing ATP formation. An electron ledger alone cannot determine the recovery of useful free energy.

A useful organizing principle is Gibbs free energy: at specified temperature and pressure a coupled process is favorable when its total $\Delta G$ is negative. For each chemical species,The relative amounts of chemical substances determine the available Gibbs free energy, beyond counting energy in individual bonds. Nutrient oxidation and light-driven chemistry can maintain nonequilibrium compositions. ATP hydrolysis can drive biosynthesis, transport and motion of molecular motors when reactions are coupled so that their total free-energy change is favorable. Breaking an inorganic phosphate bond itself costs energy; the favorable net hydrolysis includes formation and solvation of the products and depends on their thermodynamic activities.

Redox Gibbs free energy comes from transferring electrons between donors and acceptors: $\Delta G=-nF\Delta E$. Electron transfer in respiration or photosynthesis can help establish an electrochemical gradient. For a mole of ions moving from side 1 to side 2,The concentration and electrical terms together drive transport and can power ATP synthase. ATP-driven pumps can conversely build gradients. Chemiosmosis is the coupling between this gradient and chemical synthesis, not the creation of Gibbs free energy by an enzyme.

Mechanical work and elastic storage are other forms: a motor can do $\int Fdx$ or $\int \tau d\theta$, and an approximately Hookean element stores $k{x}^2/2$. ATP-driven motors convert Gibbs free energy into motion, while externally forced reverse motion can sometimes drive chemical synthesis. A photon brings energy $h\nu$; light photon absorption initiates chemistry in photosynthesis and light-driven pumps, with some energy inevitably dissipated. Living cells use these conversions for structure, movement, homeostasis and synthesis, while releasing heat and exporting entropy. At a single uniform temperature, dissipated heat cannot be completely recycled into useful work.

Let $r=a_{\mathrm{ADP}}/a_{\mathrm{ATP}}$ and use a one-molar standard state, so the inorganic phosphate activity is approximately $a_P=0.006$. With the source's stated standard hydrolysis value,The downhill proton-transfer Gibbs free energy is $F\Delta p$ for the signed driving force $\Delta p=-0.150$ V. Ideal reversible balance of one complete turn requiresSolving yieldsAt 298.15 K the estimate is $3.39\times 10^2$. Temperature is not specified in this paragraph; the first value explicitly adopts physiological temperature rather than pretending it is supplied. The unexpectedly large ADP/ATP ratio follows from using the printed standard value $-50$ kJ/mol with the stated dilute inorganic phosphate. One must not silently replace that value by another convention or treat it as the already concentration-corrected cellular hydrolysis Gibbs free energy.

This estimate assumes ideal thermodynamic activities, consistent pH and magnesium conventions, tight coupling of ten protons to three ATP, no leak or transport overhead, and operation close to reversible balance. A working cell is not in global equilibrium. Net synthesis at this fixed driving force requires $\Delta G_{\mathrm{turn}}<0$, hence $r$ above this reversible-balance threshold; finite chemical kinetics and dissipation prevent the stoichiometry alone from determining an exact physiological ratio.

A major source of ATP is chemiosmosis: an electron transport chain uses downhill electron transfer to establish a proton-motive force, and ATP synthase converts that electrochemical gradient into ATP formation. In aerobic oxidative phosphorylation, reduced carriers supply electrons, ultimately reducing oxygen to water; selected respiratory complexes couple the favorable oxidation-reduction reaction to uphill proton translocation. In a mitochondrion, this takes place across the inner membrane, creating a relatively positive, acidic exterior side and a relatively negative, alkaline matrix. Bacteria use their cell membrane. In photosynthetic systems, light-driven electron transfer can supply the gradient instead. Substrate-level phosphorylation is another ATP-producing route, so the description is not universal to every organism and condition.

The membrane $F_O$ region of ATP synthase contains a rotating ring of c-subunits next to subunit a. Two offset aqueous half-channels expose the ring's proton-binding sites to opposite membrane sides. Proton binding and release bias ring rotation down the electrochemical gradient. The central shaft transfers torque to the $F_1$ catalytic head, while a peripheral stator prevents the head from simply co-rotating. This is the ATP synthase rotary mechanism, rather than unrestricted proton leakage through a pore.

The three catalytic beta subunits cycle through different binding states as the shaft turns: ADP and inorganic phosphate bind, bound ATP is favored, then ATP is released. The binding-change mechanism uses mechanical work to alter binding affinities and product release as well as the chemical step. A full coupled revolution produces three ATP molecules; a ring with $n_c$ c-subunits transfers approximately $n_c$ protons per revolution in the tightly coupled model, or $n_c/3$ per ATP.^[ref][ref]

The overall cycle must have a favorable Gibbs free energy change. If the proton-motive force becomes too small, synthesis stops; under suitable conditions the same molecular motor can reverse, using ATP hydrolysis to pump protons uphill. A catalyst changes kinetics, not the thermodynamic condition for synthesis.

Cells store usable free energy in chemical disequilibria: reduced carbon compounds, redox carriers such as NADH, ATP relative to ADP and inorganic phosphate, ion concentration gradients and membrane voltage. These reservoirs are maintained away from equilibrium; the useful quantity is the chemical or electrochemical potential difference, not simply a bond's isolated energy. Some ATP-consuming reactions can be driven because a coupled overall reaction decreases Gibbs free energy, even when the uncoupled synthesis would not.

Oxidation of nutrients transfers reducing equivalents to electron carriers and then to an electron-transport chain. Coupled proton pumping converts part of the redox free-energy drop into a protonmotive force. ATP synthase can convert that force into ATP chemical potential, and ATP hydrolysis drives biosynthesis, transport and mechanical motion. Substrate-level phosphorylation is another ATP source; photosynthetic cells can initially supply the disequilibrium with absorbed light. These are flows with unavoidable dissipation and heat release, not independent energy-creation processes. A reservoir is depleted unless metabolism replenishes it.

Glycolysis converts glucose into two pyruvate molecules, with a net two ATP and reduced NADH; it does not directly consume molecular oxygen. Pyruvate processing and the citric acid cycle, also called the TCA cycle, release carbon dioxide and supply reduced carriers. Thus releasing carbon dioxide and consuming molecular oxygen occur at different stages.^[ref]

An electron transport chain reoxidizes carriers such as NADH. Coupling some of its redox steps to proton transport establishes an electrochemical gradient; ATP synthase can use that gradient to form ATP from adenosine diphosphate and inorganic phosphate. This is oxidative phosphorylation. A separate route, substrate-level phosphorylation, transfers a phosphate group from a reacting substrate to adenosine diphosphate. In typical eukaryotic biological cells, the respiratory chain occupies the inner membrane of a mitochondrion.^[ref]

The useful achievement is controlled transfer: fuel oxidation can replenish an ATP supply that supports active transport and synthesis. ATP is a reusable chemical carrier, not newly created energy; ATP hydrolysis and the coupled cellular process have their own net free energy balance. Some fuel energy is dissipated as heat.^[ref]

There is no universal yield of $36$ or $38$ ATP per glucose. Actual ATP recovery depends on carrier transfer routes, coupling and diversion of intermediates to other metabolism. In particular, an oxygen uptake rate cannot be converted into an ATP production rate by assuming one fixed multiplier.^[ref]